What is the relation between the proton number & arrangement of electrons in an ion and the symbols of the ions themselves? Thanks
E.g.
Al 2.8.3
Al+
2006-08-30 01:36:17 · 9 answers · asked by unquenchablethirst 2 in Science & Mathematics ➔ Chemistry
How to get the symbol of the ions of an element only by seeing the electron numbers?
2006-08-30 01:58:08 · update #1
Al as an ion is A+3 not A+ like u mentioned,the oxidation state of Oxgen is -2 and for Al is +3, proton number in an atom is equal to the number of the electrons in the outer shells of the atom.the electronic configuration depends on the number of electrons distributed in the energy levels .when an atom gain an electron it will be a negative ions , since the number of electrons more than the number of proton , if the atom lost an electron it will be positive ion , the number of proton is more than the number of electrons in the +ve ion.
2006-08-30 02:42:11 · answer #1 · answered by basimsaleh 4 · 0⤊ 0⤋
Al+ indicates a charge of a positive one, which means that one electron in one of the shells has become removed from the atom. Thus, the balance is now unbalanced with 1 extra proton. Since this state isn't stable, the ion will combine with something else to become more stable. Al 2+ would indicate 2 electrons separated and therefore 2 extra protons.
My Attempt ^
2006-08-30 08:46:57 · answer #2 · answered by descartesprotege 3 · 0⤊ 0⤋
Errr care to elaborate? I don't quite grasped your idea...
But anyway as what I understood, the relationships are:
# of electrons = to # of protons
(That's why the element is neutral)
Atomic # = # of protons
Mass # = # of protons + # of neutrons
Therefore:
# of neutrons = mass # - atomic #
The symbols of the ions themselves indicate whether they are positively or negatively charged are are quite related to chemical reactions.
Ex. H+ + Cl- = HCl
positive attract negative, much like that of a magnet
They become positively charged when they donate or give off electrons, and become negatively charged when they recieve electrons.
2006-08-30 08:54:03 · answer #3 · answered by seraph 1 · 0⤊ 0⤋
yeah, I'll take 10 points.
that Aluminum ion has a charge of 1+, so it is short one electron.
in the first shell, there are 2 electrons
there are 8 electrons in the second.
there are 3 electrons in the third.
when Aluminum gives up an electron, it will come out of its outermost valence. Most elements are this way until you get to the bigger ones, who will give an electron out of the second to last valence, because it would take more energy to split a pair of electrons in the outermost shell.
have fun, good luck diagramming that.
2006-08-30 08:47:38 · answer #4 · answered by notsureifimshy 3 · 0⤊ 0⤋
proton number=electron number...
electrons are arranged in shells like...k-shell,2 electronsthen 8,18etc...
if an ion has a +charge then it means that an electron has been removed from it and if it has a -ve charge it means that an electron has been added to it...
in the example that you have given...its Al+...so 1 electron has been removed from it..
aluminium's got 13 eletrons totally...so the arrangement is 2,8,3....now there's 1 +ve charge.....so it becomes 2,8,2...ie.2,8,3 minus 1 electron...
2006-08-30 09:26:41 · answer #5 · answered by fullmental 2 · 0⤊ 0⤋
That has practically nothing to do with the number of protons (except as how they dictate the number of electrons in a neutral atom) and everything to do with the ionization level(s) of the atom you're working with.
Doug
2006-08-30 08:43:16 · answer #6 · answered by doug_donaghue 7 · 0⤊ 0⤋
Sure!20 iif u can!!
2006-08-30 08:43:20 · answer #7 · answered by Anonymous · 0⤊ 0⤋
Do your own homework.
2006-08-30 08:41:33 · answer #8 · answered by Anonymous · 0⤊ 0⤋
What!!!!!!! I have no idea!!!!!
2006-08-30 08:39:54 · answer #9 · answered by Lucy29 1 · 0⤊ 0⤋