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If a 25 foot 1/2 inside diameter pipe was placed vetically, filled with water what would be the PSI? I don't understand the equation below.
What would be the numerical answers to Dw and G
Pressure = P = Dw x G x H
Whereby, P = Pressure in Psi
Dw = Density of Water
G = Gravity in Feet / Second^2
H = Height in feet, distance from A to B whereby
Point A is from the surface of the water
Point B is any point that you wish to calculate but
logically it won't exceed 25 feet.

2006-08-29 18:49:17 · 6 answers · asked by Im1vestr 1 in Science & Mathematics Mathematics

6 answers

The WEIGHT density of water is 62.4 lbf/ft^3.
(This is Dw x G in your equation.)
So, P = 25 * 62.4 = 1,560 lbf/ft^2 (psf)
1.560 psf / 144 in^2/ft^2 = 10.833 psig (pounds per square inch gage).
You must add local atmospheric pressure to this value to get absolute pressure (psia).

2006-08-30 00:09:56 · answer #1 · answered by Helmut 7 · 0 0

"The weight density of a material is the weight of a given volume unit of the material divided by that volume unit. An example is that a 1 cubic foot volume of water weighs 62.4 pounds. The density of water is then 62.4 pounds per cubic foot."

you have to solve Dw, based on the volume of 25 ft H , 0.5 diameter (V=pie xradius square x height), Gravity(G=32f/s>2)

2006-08-29 19:07:13 · answer #2 · answered by nobody 1 · 0 0

The pressure at any point is the height of the column above that point times the density of water.

2006-08-29 19:45:11 · answer #3 · answered by gp4rts 7 · 0 0

density of water is about 1kg / liter
G is 9,8 meter / second^2

Is this an answer to your question ?????

2006-08-29 19:09:10 · answer #4 · answered by gjmb1960 7 · 0 0

good luck

2006-08-29 19:01:07 · answer #5 · answered by jc 1 · 0 0

No

2006-08-29 18:58:03 · answer #6 · answered by Lee J 4 · 0 0

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