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1.The union of the solution sets of x+1=5, x+1<5, and x+1>5 is (-infinity, infinity).
2.The intersection of the sets {xlx>/7} and {xlx\<7} is no solution.
3.The union of the sets (-infinity,8) and (8, infinity) is {8}.
4. The intersection of the sets (-infinity, 8) and (8, infinity) is {8}.
5. The intersection of the set of rational numbers and the set of irrational numbers is {0}.
6.The union of the set of rational numbers and the set of irrational numbers is the set of real numbers.

2006-08-29 18:30:43 · 2 answers · asked by Anonymous in Education & Reference Homework Help

2 answers

1. False since it describes all points along a line that stretches from -infinity to +infinity

2. Not sure. The operators seem odd. What does \ imply?

3. False, it is -infinity,8, infinity since it is a union it joins the two sets

4. Strictly false, if -infinity=infinity. Assuming -infinity not equal to infinity, the true

5. True - they are exclusive sets

6. True since all numbers are either rational or irrational.

2006-08-30 05:08:07 · answer #1 · answered by odu83 7 · 0 0

Did you imagine this with the help of earlier posting? the first reality is authentic (case in aspect 2/3 vs 3/3... 3/3 equals a million, a million is larger than 2/3. in this example, the better numerator is the more beneficial variety). the 2d reality is fake (2/3 vs 2/2... 2/2 equals a million, a million is larger than 2/3. in this example the smaller denominator is the more beneficial variety).

2016-10-15 22:07:57 · answer #2 · answered by ? 4 · 0 0

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