Physics/Math question?

Question

"What are the horizontal and verticle components of a 10-unit vector toriented 37 degrees above the horizontal?"
Please help me i dont get this!

please explane your steps because i am a man of formula and i need one to function with this

please explane your steps

Answer 1

first you have to get an image of this toriented 37 degrees above the horizontal (you've already got it, Ok?)

make a horizontal and vertical line from the point of the vector (the point that made the 37 degrees)

make a line connecting the end of 10-unit vector to the horizontal and vertical line you have made

assume 37 degrees as A (or else...)

now you get the horizontal and vertical components of the vector

the vertical component is in the front of A --> it is sine
Fy = sine A * 10

so the horizontal component is ---> cosine
Fx = cosine A * 10

37 degrees is a special degree
remember triple phitagoras?
3 - 4 - 5
the degrees should be paired with the length of the line (small-short, medium-medium, big-long)
37 degrees is in front of 3
53 degrees is in front of 4
90 degrees is in front of 5

try to draw this triangle so you can imagine

Fy = sine A * 10
= 3/5 * 10
= 6 units

Fx = cosine A * 10
= 4/5 * 10
= 8 units

that's all

Answer 2

If you need to understand this better, draw a picture of the vector at the origin of an x, y coordinate system. Make the vector 37deg from the x axis (horizontal) and 10 units long. Draw a vertical line from the end of the vector to the x axis. The length of that vertical line is the vertical component of the vector and it forms a right triangle with the vector and the x-axis. The definition of the sine of the angle is side opposite over hypotenuse. Here, the side opposite is the vertical line, the vector is the hypotenuse. Therefore, hypotenuse times sine of the angle is side opposite: vertical component is sine 37 time vector length. Similarly, the length of the segment of x-axis between origin and where the vertical line meets the x-axis it the horizontal component (side adjacent), and by similar reasoning you get that the horizontal component is vector length times cosine 37.

Answer 3

You can solve it by just considering the vector the hypoteneuse of a right triangle with a length of ten.

Answer 4

horizontal: 10*cos(37)
vertical: 10*sin(37)