(x-2)(x+2)/(x-2)=(x+2), x≠2
(-∞,2)u(2,∞)
2006-08-29 16:15:16
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answer #1
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answered by venomfx 4
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Notice that it reduces:
f(x) = (x^2 - 4)/(x-2)
= (x+2)(x-2)/(x-2)
= x+2
That's a line, so the range would be all reals. However, the domain of the original function excluded x = 2, so the range would be all reals except 4.
2006-08-29 16:10:52
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answer #2
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answered by Anonymous
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(x^2 - 4)/(x - 2)
((x - 2)(x + 2))/(x - 2)
x + 2
ANS : x + 2 with a gap at x = 2
for a graph, go to http://www.calculator.com/calcs/GCalc.html
type in (x^2 - 4)/(x - 2), if you look really close at (2,4), you will see a gap.
2006-08-29 16:15:44
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answer #3
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answered by Sherman81 6
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i think the range is the result of the problem, like the solution when you substitute x to find f.
2006-08-29 16:09:53
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answer #4
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answered by xm4 2
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