Ice has heat of fusion of 3.34 times 10 5 j/kg and specific heat of 2060 j/kg degrees c.How much heat must be?

Question

absorbed by 2.6 kg of ice at - 27 degrees c to cause it to all melt into liquid?

Answer 1

To get it frm ice at -27C to ice at 0C, 2060 x 2.6 x 27 = 144,600 j

To melt the 0C ice into 0C water, 334,000 x 2.6 = 868,400 j

Total = 1,013,000 j

"heat of fusion" is the heat needed to melt a solid

"specific heat" is the heat needed to raise the temperature of a material 1 degree C without a phase change.