2006-08-29 15:26:27 · 4 answers · asked by Jerry 4 in Science & Mathematics ➔ Mathematics
No. e^x^2=e^(x^2) by convention.
2sin(8x) cos(8x)=sin(16x) by the sine double angle formula.
2006-08-29 15:30:36 · answer #1 · answered by mathematician 7 · 1⤊ 0⤋
The answer to your first question is no, if I understand what you have written correctly. The RHS of the equation asks for the value of e to x squared,while the LHS asks for e to two x, as when you raise a power to a power, you multiply the two powers together.
As for your second question, in this case 2sin(kx)*cos(kx) is a trigonometric identity, which equals sin(2kx), so in this case it equals sin(16x).
2006-08-29 22:34:03 · answer #2 · answered by Noachr 2 · 0⤊ 1⤋
(e^x)^2 = e^(2x)
2sin8x*cos8x = sin(2*8x) = sin(16x)
2006-08-29 23:15:27 · answer #3 · answered by qwert 5 · 0⤊ 0⤋
(e^x)^2 = e^(2x) not e^(x^2)
Use the identity sin(2a) = 2*sina*cosa; from this you can see that 2*sin(8x)*cos(8x) = sin(16x)
2006-08-29 22:34:42 · answer #4 · answered by gp4rts 7 · 0⤊ 1⤋