math
2006-08-29 15:14:07 · 10 answers · asked by TODD P 1 in Science & Mathematics ➔ Mathematics
4050, 4245.
=)
2006-08-29 15:18:52 · answer #1 · answered by Jess 2 · 0⤊ 0⤋
4050 (3 x 1350) (5 x 810)
4245 (3 X 1415) (5 x 849)
To figure out if a number is divisible by 5, check out the last digit (the digit in the 'ones' place). Numbers that end in '5' or '0' are divisible by 5
To figure out if a number is divisible by 3, add the digits; keep adding until you get a 1 digit number. If the sum of the digits is 3, 6, or 9, the number is divisible by 3.
All 4 numbers end in '0' or '5', so they are all divisible by 5.
Which are divisible by 3? Add the digits to find out.
3 + 0 + 4 + 0 = 7; 7 isn't 3 or 6 or 9
4 + 0 + 5 + 0 = 9; 9
2 + 3 + 1 + 5 = 11; 1 + 1 = 2
4 + 2 + 4 + 5 = 15; 1 + 5 = 6
enjoy!
2006-08-29 22:24:18 · answer #2 · answered by slly d 1 · 0⤊ 0⤋
If it ends in a 0 or a 5, it is divisible by 5. Add up all the digits, if they add up to a number divisible by 3, then the number is divisible by 3.
All the numbers listed above are divisible by 5.
Here is the analysis for 3;
3+0+4+0=7
7 is not divisible by 3 therefore 3040 is not divisible by 3
4+0+5+0 = 9
9 is divisible by 3 therefore 4050 is divisible by 3.
2+3+1+5=11
11 is not divisible by 3 therefore 2315 is not divisible by 3.
4+2+4+5=15
15 is divisible by 3 therefore 4245 is divisible by 3.
2006-08-29 22:24:07 · answer #3 · answered by eric l 6 · 0⤊ 0⤋
They are all divisible by 5 as they all end in a multiple of 5. 4050 and 4245 are the only ones which are also divisible by 3.
2006-08-29 22:18:58 · answer #4 · answered by fat_albert_999 5 · 0⤊ 0⤋
I refuse to do your homework for you, because you'll never learn that way, but I'll tell you this much...
If you add the digits in a number, and the result is divisible by 3, the whole number is divisible by 3. For example: 8571 8+5+7+1 = 21. 21 is divisible by 3, therefore 8571 is also divisible by 3.
As for what's divisible by 5, the answer is all in the last digit.
You're on your own...have fun. :) And remember - knowledge is power.
2006-08-29 22:28:28 · answer #5 · answered by Tish 5 · 0⤊ 0⤋
A number divisible by 5 would end in a 0 or 5... all four numbers meet this requirement.
A number divisible by 3 would have the sum of its digits be divisible by 3 as well.
3040 -> 7
4050 -> 9
2315 ->11
4245 -> 15
4050 and 4245 are both divisible by three, so those are your two answers.
2006-08-29 22:21:08 · answer #6 · answered by Kyrix 6 · 1⤊ 0⤋
They are all divisible by five.
4050 and 4245 are divisible by 3.
So 4050 and 4245 are the only ones divisible by both 3 and 5.
2006-08-29 22:21:24 · answer #7 · answered by Maestro bestofthebest 2 · 0⤊ 0⤋
4050 4245
2006-08-29 22:28:01 · answer #8 · answered by on theWaves 3 · 0⤊ 0⤋
4050 and 4245
2006-08-29 22:18:58 · answer #9 · answered by Walter 2 · 0⤊ 0⤋
4050, 4245
2006-08-29 23:23:40 · answer #10 · answered by cyrus 2 · 0⤊ 0⤋