The one who eats the $10 dinner pays 10/26 of $16 and the other pays 16/26 of $16.
2006-08-29 13:54:20
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answer #1
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answered by zee_prime 6
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"Buy one, get one free" means the $10 dinner is free. So, the total for both meals is $16. To split it fairly between two people, divide $16 by 2 people. That's $8 per person.
OR
Add up what the bill should have cost: $10 + $16 = $26. Then, 10/26 would be 38% and 16/26 would be 62%. So, 38% of the real total cost is $6.08 (for the person who bought the $10 dinner) and 62% is $9.92 (for the person who bought the $16 dinner).
2006-08-29 21:06:15
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answer #2
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answered by fibr 2
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This isn't really a math question so much as a judgement call. If they both pay $8, then the person with the $16 meal got his for half price while the other person paid 80% of the cost of his meal. If that seems fair, then so be it.
If the $16 person pays $11 and the $10 person pays $5, then they both save $5.
Your call.
2006-08-29 20:57:15
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answer #3
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answered by Anonymous
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If they are good friends - $8 each
Otherwise do what zprime said 10/26 of $16 and 16/26 of $16
2006-08-29 20:58:59
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answer #4
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answered by jdomanico 4
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You could say that one pays 10/26 of the bill and the other pays 16/26 of it. Multiply $16 by these fractions to see what each pays.
$9.85 and$6.15
2006-08-29 20:55:46
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answer #5
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answered by hayharbr 7
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$16 / 2 = $8 each.
2006-08-29 21:57:52
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answer #6
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answered by Anonymous
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16/26 times 16 = 9.85
10/26 times 16 = 6.15
2006-08-29 22:20:21
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answer #7
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answered by MollyMAM 6
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the friend who ate the $16 will pay $10 and the friend who ate the $10 dinner pay $6.
2006-08-29 20:56:01
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answer #8
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answered by miss_moet 2
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Let us call the value of there dinners V
V1=16
V2=10
ratio v1:v2= 1.6:1
total cost =16
total v=26
16/26=0.6154
16x0.6154=$9.85
10x0.6154=6.15
2006-08-29 20:57:53
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answer #9
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answered by Sleeping Troll 5
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The person should have ordered a $ 16.00 dollar dinner since it was free.
2006-08-29 21:34:19
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answer #10
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answered by ENDURAMAN 4
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