How do you sovle (3x^2+13x-55) divided by (x+7)?

Answer 1

(3x^2+13x-55) / (x+7)

Step 1;
{ first you need to remover ' 3x^2'
{( x+7) * 3x = 3x^2 + 21 = ( 3x^2 + 21 )
3x^2 +13x -55 -( 3x^2 + 21 ) = 3x^2 +13x -55-3x^2 -21x = 8x - 55

3x^2 +13x -55 / (x+7) = ((x+7) * (3x )) +8x -55
▪ 8x -55 is remainder

Step2;
{( x+7) * 8= 8x + 56
8x -55 - ( 8x + 56 ) =8x -55 - 8x - 56 = - 111

-111 is remainder.

Therefor (3x^2+13x-55) / (x+7) = (3x+8)(x+7) +(-111)

Good luck

Answer 2

set it up like long devision. Then you find how many times x (from x+7) goes into 3x^2. 3x. Then distribute that through x+7 and you get 3x^2 + 21x. Subtract that away just like you would do a regular long division problem, but when you subtract it away, make sure that you change all of the signs.
When you get the remainder, you find out how many times x (from x +7) will go into that. Continue on until you can no longer divide out.

It's simple once you get going and in the groove with it.

Answer 3

Of course, we should also check our results. (3x-8)*(x+7) == 3*x^2 + 21x - 8x - 56
== 3*x^2 + 13x - 56

So, the "remainder" is -1.

Answer 4

(3x^2 + 13x - 55)/(x + 7)

-7`|``3``13``|``-55
````|`````-21``|``56
-----------------------
````|``3```-8 |``````1

ANS : 3x - 8 R 1 or 3x - 8 + (1/(x + 7))

Answer 5

the the relax theorem: even as P(x) is split by using x-a, the the relax is P(a) The polynomial P(x) is being divided by using x+a million, or x-(-a million). the the relax is P(-a million): (-a million)^3 + 3(-a million)^2 - 2(-a million) + 7 -a million + 3 + 2 + 7 11 the the relax is 11.

Answer 6

Just do it like another dividing system
-------___3x - 8
x+7 / 3x^2+13x+55
______3x^2+21x_____ -
__________-8x +55
__________-8x -56__-
______________111

So, the result is (3x-8) and the remainder is 111

Answer 7

solve the above equation and cancel (x+7)

Answer 8

I ask somebody smart.

Answer 9

coculater

Answer 10

.use math.