increasing
(P1V1)/T1 =(P2V2)/T2
in this question, T remain constant so
P1V1=P2V2
If you decrease the volume, V2
So, in order to balanve the equation, P1
2006-08-29 13:11:38
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answer #1
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answered by Logic + 1
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Boyle's Law : For a fixed mass of gas at constant temperature, the volume is inversely proportional to its pressure.
I know you said 9th grade but how do you decrease the volume of a gas so that it affects the pressure? Shouldn't that be the other way around : change the pressure so that the volume is affected? If the pressure is increased, the volume decreases.
2006-08-29 13:23:08
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answer #2
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answered by flandargo 5
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assuming the gasoline follows ideal habit, you should use the ideal gasoline regulation: PV=nRT the position p=stress, v=volume, n=type of moles, R=consistent , T=temperature following this regulation, the stress is rapidly proportional to the volume. because the form of moles are not replacing, if the stress will advance, the volume ought to shrink, and vice versa. if the stress is higher, the molecules of a gasoline holiday at more beneficial speeds. frequently, deltaT ought to also be considered, yet i'm not sensible once you're also asking about that.
2016-11-23 13:34:27
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answer #3
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answered by ? 4
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On decreasing the volume the pressure of the gas get increase.........Boyle's law.
2006-08-29 13:38:18
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answer #4
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answered by moosa 5
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increased pressure
2006-08-29 13:05:03
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answer #5
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answered by Anonymous
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