solve each system using substitution
1) y=4x-8
y=2x+10
2) m=5p+8
m= - 10p + 3
3) y=x-2
2x+2y=4
2006-08-29 12:54:56 · 4 answers · asked by JOLKK 1 in Education & Reference ➔ Homework Help
1) 2x+10=4x-8
18=2x
x=9
2) 5p +8 = -10p + 3
15p = -5
p = -1/3
3) 2x +2x-4 = 4
4x=8
x=2
2006-08-29 13:03:09 · answer #1 · answered by odu83 7 · 0⤊ 0⤋
(1) 2x + 10= 4x - 8
2x - 4x= -10 - 8
-2x= -18
x= -18/-2
x=9
(2) -10p + 3= 5p + 8
-10p - 5p= 8-3
-15p= 5
p= 5/-15
p= -1/3
(3) 2x + 2 (x - 2)= 4
2x + 2x - 4= 4
4x= 4+4
4x= 8
x= 8/4
x= 2
sustitute the answers of x into all the equations and both equations will give the same answer
2006-08-29 20:12:38 · answer #2 · answered by evanescent_eclipse 3 · 0⤊ 0⤋
3)
1. solve for x
2. plug that answer into the x in the second equation
3. plug the final answer for y into one of the equations to get the final answer for x
y = x - 2
y + 2 = x
2(y+2) + 2y = 4
2y + 4 + 2y = 4
4y = 4
y = 0
0 + 2 = 2 = x
Hope that helps!
2006-08-29 20:04:22 · answer #3 · answered by Saritah 5 · 0⤊ 0⤋
little rusty
2006-08-29 20:03:19 · answer #4 · answered by kameasmomma 1 · 0⤊ 0⤋