2006-08-29 12:38:36 · 5 answers · asked by JEFF H 1 in Science & Mathematics ➔ Mathematics
Well, start by dividing 63 by 3, since that will give you an approximation. Then figure the rest out by trial and error. The answer is 20, 21, 22.
2006-08-29 12:41:09 · answer #1 · answered by Walter 2 · 0⤊ 0⤋
Using arithmetic, divide 63 by 3. You get 21. Therefore, the three consecutive numbers are 20, 21, and 22.
Using algebra, x + (x + 1) + (x - 1) = 3x = 63.
so x = 21
x + 1 = 22
x - 1 = 20
2006-08-29 20:01:36 · answer #2 · answered by RG 4 · 0⤊ 0⤋
Consecutive would mean that each number is one more then the last, and since you do not know which number you are starting with call it x.
Since there are 3 integers we would need (x)+(x+1)+(x+2).
3x+3=63
3x=60
x=20
20,21,22
2006-08-29 19:44:27 · answer #3 · answered by firefly 3 · 0⤊ 0⤋
x + (x + 1) + (x + 2) = 63
x + x + 1 + x + 2 = 63
3x + 3 = 63
3x = 60
x = 20
ANS : 20, 21, and 22
2006-08-29 20:42:06 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋
write an equation:
x + (x+1) + (x+2)
u know this because they are consecutive
x+ (x+1) + (x+2) = 63
3x + 3 = 63
3x = 60
x= 20
check:
20 + 21 + 22 = 63
tada! :)
2006-08-29 19:41:15 · answer #5 · answered by sasmallworld 6 · 1⤊ 0⤋