algebra 1 homework?

Question

please tell me how to do these problems.

xy ^2(3x-2y) and then there is another one that is


ab(a^2+3b^2-4ab)

(y+5)^2

(4n+1)+(n^2-5n)

^ means to that power so 4^2 means 4 to the second power.

Answer 1

we're just simplifying right? multiply the #'s and when there are variables, u add them together (example x ^1 x^2 = x ^1+2 = x^3

1) xy^2(3x-2y)

3x^2y^2-2xy^3

2) a^3b + 3ab^3 -4a^2b^2

3) (y+5)^2 = (y+5)(y+5)
y^2 +5y +5y +25

y^2 + 10y +25


4) (4n+1)+(n^2-5n)

4n + 1 + n^2 - 5n

n^2 -n + 1

Answer 2

The first and second problem are solved with the distributive property. Take the term on the outside and multiply by each of the terms on the inside of the parenthesis.

The third problem means to multiply (y+5) times itself...(y+5)(y+5) Use FOIL or distribute twice.

The last problem is pretty simple. Drop the parenthesis and combine like terms. Remember that like terms have the same variables raised to the same powers.

Good luck.

Answer 3

1. x ( y y) ( 3x-2y). multiply the two parenthesis using distrebution

2. (y+5) ( y+5). use distrebution.

i need to do my homework so someone else can answer the other two.

Answer 4

wat is da arrows for?