Absolute value is the positive of any value.
So if x = -8, then
The absolute value of x, denoted by |x|, would be 8
That is |x|=8
And if x = 9, then
Then |x| = 9
Good luck!
=)
2006-08-29 10:44:26
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answer #1
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answered by Jess 2
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Absolute value, as other writers have stated, is the value's distance from zero on a number line. Hence |-2| is 2, and |+2| is also 2. Fairly useless, except when it comes to complex numbers, (numbers with both a real and an imaginary part) which are represented on a two-dimensional axis. Hence, | 3 + 4i | is 5, for instance.
2006-08-29 10:49:54
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answer #2
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answered by trentrockport 5
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Absolute value is the distance from zero. Since distance can never be negative, the answer to an absolute value problem is always positive.
2006-08-29 10:46:35
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answer #3
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answered by smartypants909 7
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absolute value is a measure of distance.
think of a number line:
-3 to -2 to -1 to 0 to 1 to 2 to 3
the absolute value of of -3 otherwise known as l-3l is 3
because it is 3 away from zero
2006-08-29 10:46:52
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answer #4
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answered by jannc2006 1
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Think of it in terms of distance, how far a number is away from 0. Since distance can not be negitive, neither can absolute value.
2006-08-29 10:46:39
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answer #5
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answered by who be boo? 5
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Absolute in science refers to a fixed value -- like the speed of light which never varies.
This is as opposed to relative value -- like the flow of time which is relative to motion.
2006-08-29 10:47:15
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answer #6
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answered by Jay 6
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i know how you do it, but not why it's called absolute value. when you see the pair of straight up and down lines with a number in it, that number will ALWAYS be positive.
ex. |-5| = 5
ex. |5| = 5
hope that helps! good luck!!
2006-08-29 10:49:16
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answer #7
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answered by Jade Poe 2
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It is the value of the number....no negatives, no positives.
Example l-4l=4
2006-08-29 10:45:29
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answer #8
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answered by voandginger 4
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It is the distance from 0 -
2006-08-29 10:46:29
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answer #9
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answered by M 1
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It is the function a(x) = (x^2)^0.5, x a member of the Reals.
2006-08-29 10:46:56
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answer #10
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answered by Anonymous
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