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tan^-1(x)

The choices are:
a) 1 / sqrt(1 - x^2)
b) 1 / sqrt(x^2 - 1)
c) 1 / (1 + x^2)
d) 1 / (1 - x^2)

2006-08-29 10:15:36 · 2 answers · asked by dodido 3 in Science & Mathematics Mathematics

2 answers

The answer is C:

Proof:

tan﴾tan ‾ ¹(x)﴿ = x for all x

let y = tan ‾ ¹(x)

so we have:

tan(y) = x

now differentiate both sides (you need to use implicit differentiation)

sec²(y)dy/dx = 1

dy/dx = 1/ sec²(y)

by trig. Identity:

dy/dx = 1/ ﴾ 1 + tan²(y) ﴿

But look above, y = tan ‾ ¹(x), so tan²(y) = tan²( tan ‾ ¹(x)) = x²

Thus

dy/dx = 1/ ﴾ 1 + x²﴿

QED

2006-08-29 10:43:23 · answer #1 · answered by Anonymous · 2 0

d

2006-08-29 17:20:27 · answer #2 · answered by The Guy 3 · 0 0

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