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Three friends went to a hotel. The bill was $75.
Each one contributed $25
The waiter took the bill to the cashier.
The cashier was happy & decided to give them a discount of $ 5 & asked the waiter to return them $ 5
Now the waiter was confused. How to distribute $ 5 among 3 persons?
He kept $ 2 in his pocket & gave one dollar to each one of the 3 persons.
So initially each one had contributed $ 25. Now as they are given 1 dollar back, their contribution reduces to $ 24.
They all contributed $ 24 -- that is 24x3=72 & 2 dollars are in the waiters pocket.
The total becomes 74. But they had paid $ 75.
Where is the remaining 1 dollar?

2006-08-29 09:04:33 · 13 answers · asked by Andy 1 in Science & Mathematics Mathematics

13 answers

There is no remaining dollar.

The trick here is how much does the cashier have.

That is the cashier has $70 at the end. They guys paid $72. So the real question is - where is the $2 between what the guys paid ($72) and what the cashier has ($70).

Obviously this is what the waiter has.

This is one of those fun - lets mix up two equation problems. They are always fun and do a great job of tricking the mind.

So first transaction - pay 75. Cashier only takes 70. the 3 Guys each get 1 back and waiter gets 2. So 70+3+2=75

Second transaction is that they have only paid 72. 70 to cashier and 2 to waiter. So 70+2=72

So alas, there is no missing dollar.

I guess maybe further explanation would help. Is that the line "that is 24X3=72 & 2 dollars are in the waiters pocket. The total becomes 74" is simply worng and where everything gets offtrack. It is true that 24X3=72 but you subtract (not add) the $2 in the waiters pocket. Which gives you 70$ - which is exactly what the cashier has.

Cheers.

2006-08-29 11:21:31 · answer #1 · answered by movielandlawsuit 1 · 0 0

The $24 they each paid INCLUDES the money in the waiter's pocket. The total is $72 paid, less $2 in the waiter's pocket means they paid $70 for the meals. The cashier received $75, less $5 discount, is the same: $70.

2006-08-29 16:17:04 · answer #2 · answered by Marvinator 7 · 0 0

There is no remaining dollar.

Look at it another way.

Originally the bill was $75. They were then given a $5 discount which then brings the bill to $70. The waiter gave $1 each to the three men for a total of $3 and kept the other $2 for himself. All the money is accounted for.

2006-08-29 16:14:50 · answer #3 · answered by xox_bass_player_xox 6 · 0 0

The cashier has $70, the waiter's $2 should be added to the cashier's making $72. The other $3 should be added to 72 making $75.

2006-08-29 16:16:35 · answer #4 · answered by Pigeons 2 · 0 0

the bill was $75 and they paid $25 each.
after discount they only had to pay $70 so they get $5 back.but waiter took $2 so they ended up paying $72 because as a group they were $2 short.
its just a play of words. a little like the proof of 1=2.

2006-08-29 16:29:12 · answer #5 · answered by jainapatel94 1 · 0 0

They didn't pay $75. They only paid $70 plus $2 that went to the waiter. The total they paid all together was $72.

2006-08-29 16:15:57 · answer #6 · answered by dashka 2 · 0 0

Why are you asking the same question again with different amounts?
You subtract the $2 from the $72, not add it. They didn't pay $75 after they got their dollar back, they paid $72, then he has the remaining $2 which takes it to $70.

2006-08-29 16:11:44 · answer #7 · answered by Anonymous · 0 0

in the pocket of the waiter. they paid in total 73dollars. the waiter has the other 2.

2006-08-29 16:23:49 · answer #8 · answered by LouLou 3 · 0 0

ok
-75$ + (5-2) = -73$

they paid out a total of 73$

2006-08-29 16:12:02 · answer #9 · answered by Jun 2 · 0 0

It was stolen by Space Aliens and it (along with the millions of other dollars missing from variants of this dumbass problem) is being used to help finance a conspiracy to experiment with human-alien gene mutation in Area 51.


Doug

2006-08-29 16:12:54 · answer #10 · answered by doug_donaghue 7 · 1 0

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