2 (x+4) - 8 = 2x + 1
2x+8-8 = 2x +1
2x = 2x +1
x = 1
??????????????
2006-08-29 08:13:58 · 21 answers · asked by laurali_love 3 in Science & Mathematics ➔ Mathematics
No solution. at:
2x = 2x + 1, you have to subtract 2x from both sides, so, you get:
2x - 2x = 1. 0 obviously doesn't = 1.
What you have are 2 parallel lines with slope of 2/1. 2x interects the origin, and 2x + 1 interesects the y axis at 1. I think, it's been awhile, but I think I'm right.
2006-08-29 08:21:06 · answer #1 · answered by Manny 6 · 1⤊ 0⤋
Not quite. This equation doesn't have an answer. If you graph both sides of the equation, you'll find that the two lines run parallel and never cross. Since they never cross, there is no answer that satisfies both equations at the same time. It looked like at the end there with the equation 2x=2x+1 you tried to subtract 2x from both sides, but remember it is a multiplication deal (2 times x on both sides).
there is no answer and this is a trick question. Probably to get you to see the slope of the equations are the same (2) but the starting points (0 and 1) are different. Same slope means the same angle going up in the graph and they run parallel.
2006-08-29 08:30:11 · answer #2 · answered by Anonymous · 1⤊ 0⤋
Obviously you are not right.
This can not be true for any value of x.
Up to your third line you are fine. But after that if you subtract 2x from both sides you get 0=1, which is not possible. Hence your equation has no solution.
If you plot y=2(x+4)-8, and y=2x+1, these are two parallel lines. Hence they will never meet. So new solution.
2006-08-29 08:23:13 · answer #3 · answered by curious 4 · 0⤊ 0⤋
2(x + 4) - 8 = 2x + 1
2(x + 4) = 2x + 9
2x + 8 = 2x + 9
0x = 1
x = 1/0
x = Undefined
if it had been 2x = x + 1, then the answer would be 1.
2006-08-29 12:37:21 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋
Wrong. The answer is no solution because in the second to last stage of the problem, you said 2x=2x+1. Then divide 2x and 2x and get 0=1. Sorry, try again.
2006-08-29 08:23:24 · answer #5 · answered by gamerzaddiction 2 · 0⤊ 0⤋
isn't right:
2 (x+4) - 8 = 2x + 1 (ok)
2x+8-8 = 2x +1 (ok)
you pass all "x" to one side,
2x = 2x +1
0 = 2x - 2x + 1
Cancel "2x"
0 = 1, is impossible so, the ecuation has no solution
2006-08-29 08:20:33 · answer #6 · answered by GN 3 · 1⤊ 0⤋
You left out a step. You need to isolate x on one side of the equation. Your next step, then, would be to subtract 2x from both sides, leaving you with 0=1, meaning this problem has not solution.
2006-08-29 08:21:58 · answer #7 · answered by cool_breeze_2444 6 · 0⤊ 0⤋
Nope, I'm afraid not.
The correct answer is that there is NO SOLUTION.
In the third step, you went from 2x = 2x + 1, to x = 1.
Instead, subtract 2x from both sides, and you get 0 = 1, which is impossible, and means there's no possible solution.
2006-08-29 08:15:53 · answer #8 · answered by rahidz2003 6 · 3⤊ 0⤋
the problem is impossible; because after 2x=2x+1 it comes to 0=1 which is false
2006-08-29 08:16:41 · answer #9 · answered by L'Aubergiste 2 · 1⤊ 0⤋
Let me tell you a better way to figure out if your answer is right or not.
Just substitute the value of x in the original equation and see if it holds.
Obviously, in this case it does not because when you have
2x = 2x + 1
There is no solution for x.
2006-08-29 09:11:15 · answer #10 · answered by DG 3 · 0⤊ 0⤋