find the distance between (3,8) and (6,4)?

Answer 1

Well sweetheart this is distance formula ;
if a (xa , ya) & b (xb ,yb)
so we have ;
● d = √[ (yb - ya )^2 + (xb - xa)^2 ]
If a (3,8) ; xa = 3 & ya = 8
&
b (6,4) ; xb = 6 & yb = 4

so ;

▪ d = √[ (4 - 8)^2 + (6 - 3)^2 ]
▪ d = √[ (-4)^2 + (-3)^2 ]
▪ d = √(16 + 9)
▪ d = √ (25)
▪ d = 5

Good Luck dear.

Answer 2

5

Answer 3

5

Answer 4

Use Pythagoras's Theorem take the Square root of thne sum of the differences squared, orb 6-3=3Squared is 9, and 8-4=4 Squared is 16. 9+16 is 25 the squareroot of 25 is 5

Answer 5

D = sqrt((x2 - x1)^2 + (y2 - y1)^2)

(3,8) and (6,4)
D = sqrt((6 - 3)^2 + (4 - 8)^2)
D = sqrt(3^2 + (-4)^2)
D = sqrt(9 + 16)
D = sqrt(25)
D = 5

ANS : 5

Answer 6

Take a blank sheet of paper, take a ruler and pencil and draw a line on that paper..
put a zero in the middle and then count out from that zero, from one to 7 on the right side, then do the same on the left side..
Next, draw a vertical line directly at the zero, and make it 10 counts above, and 10 counts below so you can cover this range... then do the rest of the homework your teacher told you to do.

Answer 7

Distance formula.

Distance = sqrt[ (x1 - x2)^2 + (y1 - y2)^2 ]

So you get:

D = sqrt [ (3)^2 + (-4)^2 ]

Or:

D = sqrt [ 9+16 ]

D = sqrt(25)

D = 5

Answer 8

d = sqrt[ (y2 - y1)^2 + (x2 - x1)^2 ]

d = sqrt[ (4 - 8)^2 + (6 - 3)^2 ]

d = sqrt[ 16 + 9 ]

d = sqrt[ 25 ]

d = 5

Answer 9

use the distance formula
distance=rt [(x1-x2)^2+(y1-y2)^2]
=rt[(6-3)^2+(4-8)^2]
=rt(9+16)=rt 25=5

Answer 10

you can use the formula D=((x^2 - e^2) +(y^2- d^2))^1/2 where (x,y) and (e,d) are the coordinates