i cant seen to get this answer....
(4x7y-2)-4
The 7 and -2 inside the parenthesis are exponents and so is the -4 outside the parenthesis. .
I've tried every way and i cant get it.. please help
2006-08-29 06:30:17 · 7 answers · asked by laural8477 3 in Education & Reference ➔ Homework Help
(4X^7 Y^-2)^ (-4)
= 4^(-4)[X^(-28)] [Y^8]
Y^8
---------- that is,
4^4[X^28]
Y^8
-----------
256X^28
Good luck.
2006-08-29 06:59:21 · answer #1 · answered by rgsoni 2 · 0⤊ 0⤋
(4x7y-2)-4
you do what is in parenthesis 1st.
4x7=28 therefore (28y-2)-4= (26y)-4 =(22y)
2006-08-29 13:39:03 · answer #2 · answered by Neptune2bsure 6 · 1⤊ 0⤋
They -4 is multiplied by the answer you get from the ( )
2006-08-29 13:36:48 · answer #3 · answered by Mika 2 · 0⤊ 1⤋
(y^8)/(256*x^28)
same as the above answer.
2006-08-29 13:53:55 · answer #4 · answered by a_liberal_economist 3 · 1⤊ 0⤋
(4X^7 Y^-2)^ (-4)
= 4^(-4)[X^(-28)] [Y^8]
Y^8
_________that is,
4^4[X^28]
Y^8
_____________
256X^28
2006-08-29 14:51:30 · answer #5 · answered by Ely 3 · 0⤊ 0⤋
(4x^7y^-2)^-4
the exponents multiply....
(4)^-4(x)^-28(y)^8
x^-28(y^8)
________
256
?? i hope that's right..good luck~
2006-08-29 13:45:58 · answer #6 · answered by sasmallworld 6 · 1⤊ 1⤋
it is 4X^-28Y^8 formula( a^m)^n=a^mn
2006-08-29 13:34:21 · answer #7 · answered by raj 7 · 0⤊ 1⤋