I need to figure out how many Yards I need for an 18in Dia by 4' deep footing
2006-08-29 06:16:32 · 7 answers · asked by dononvan_666 2 in Home & Garden ➔ Do It Yourself (DIY)
Plenty of web based calculators. 9 feet by 9 feet 4 inches thick.
check this website
http://www.concretenetwork.com/concrete/howmuch/calculator.htm
2006-08-29 06:24:19 · answer #1 · answered by mpw 1 · 0⤊ 0⤋
You will need 2.25 cubic feet.
A 60 lb. bag of Redimix concrete is .5 or one half a cubic foot. Five bags will pour the footing you are making.
Please note, building codes in some areas require certain minimum strengths for concrete. It can change from area to area and intended usage can cause variants as well. Bags of Redimix may or may not meet those requirements.
Good luck, and BTW try to mix all the concrete for the pour at one time. It helps in uniformity and there won't be any weak places where one pour has to bond to a previous pour.
I do a lot of this sort of thing, contact me through my profile if you have any more questions.
2006-08-29 13:40:45 · answer #2 · answered by gimpalomg 7 · 0⤊ 0⤋
do you mean how much concrete is in 1 cubic yard (yd^3)
well... one yd3
as for how many you need...
you find the volume...
which is 12208.32 cubic inches = 7.065 cu. ft = .21666666666666666666666666666... cubic yds
so order .21666666666...
or get a hoe, a wheelbarrow, and a few bags of quikcrete or so :)
2006-08-29 13:29:33 · answer #3 · answered by twister 3 · 0⤊ 0⤋
for your size hole all you need is 2 bags from home depot or lows. I'm a mason contractor, that is all you need for that. I just thought it would be easier to tell you how munch you need, since everybody already told you how to figure it out.
2006-08-29 20:54:09 · answer #4 · answered by mike67333 6 · 1⤊ 0⤋
27 cubic feet
2006-08-29 20:46:48 · answer #5 · answered by Dave 3 · 0⤊ 0⤋
Pi(1.5)^2/4 = 7 cu. ft. = 1/4 cu. yd.
2006-08-29 13:25:54 · answer #6 · answered by Snogood 3 · 0⤊ 0⤋
one yard is one "cubic "yard. 3'X3'X3'
2006-08-29 13:23:32 · answer #7 · answered by Norman 7 · 0⤊ 0⤋