sigh, i can't let this one go unanswered... some of the answers are just too painful (ie "increases linearly along the radius..." blah blah blah. why BS so much if your answer is wrong?).
anyway, the answer... you would weigh the most at either of the poles. the earth is not round (NOR IS IT PEAR SHAPED!!!), but is rather flattened slightly into a disk. whoever said death valley is the lowest point on earth apparently doesnt understand the difference between height compared to sea level and height relative to the center of the earth. for this reason the poles are, on average, closer to the center of the earth than any point along the equator.
cutting any fancy pants BS out of the answer and playing it to you straight, gravity is a function which is INVERSE (or divided by) the distance between the two objects. that means that the closer the centers of mass of the two objects are, the stronger the gravitational force between them. in other words, you wouldn't want to be on the equator at all because you'd be farther out... and to say that those at the equator have more mass under them is ridiculous. for calculating gravitational effects, all objects can be treated as a point mass located right at the center of mass, so being at the equator doesnt help AT ALL!!!
second, if you've ever ridden a childs little spinning toy at the park (can never remember what those things are called) and you stand at the center, you spin around but there's not any great pull out to the sides. that's akin to standing on one of the poles of the earth. now, if you stood out to the side of this childs toy, we all know that the inertia of spinning (what we call centrifugal force) causes you to feel like you're being thrown out to the sides. this is like standing on the equator, where that feeling of being thrown out to the sides makes you feel lighter. thus being at the equator both increases your distance from the earths center of mass AND has the added negative caveat that centrifugal force is throwing you out from the planet as well.
2006-08-29 04:19:30
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answer #1
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answered by promethius9594 6
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The Earth is an oblate spheroid. That means very, very slightly pear-shaped.
You weigh more if you are closer to the center of mass, so I would say you weigh the most at the South Pole.
We are talking about a ridiculously tiny fraction of a gram, remember. You will never feel the difference.
I did not make up the pear-shaped thing. Quote:
"Even the oblate-spheroidal notion of the earth is wrong, strictly speaking. In 1958, when the satellite Vanguard I was put into orbit about the earth, it was able to measure the local gravitational pull of the earth--and therefore its shape--with unprecedented precision. It turned out that the equatorial bulge south of the equator was slightly bulgier than the bulge north of the equator, and that the South Pole sea level was slightly nearer the center of the earth than the North Pole sea level was.
"There seemed no other way of describing this than by saying the earth was pear-shaped."
Unquote.
Maybe the information is old, but that's what I found. Now that Promethius (below) has his degree in physics, perhaps he can move on to charm school.
As for David M.'s novel definition of weight, he seems to be talking about mass. Mass is constant. Weight changes depending on the strength of the gravitational field acting on a mass, which is why you'd be only 1/6 your normal weight if you went to the Moon. Don't tell David that, though.
2006-08-29 03:50:47
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answer #2
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answered by KALEL 4
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I have to disagree with David. A pound is a unit of force. A person's weight is the force with which their body is attracted toward the center of the earth. Their mass is always compared to a standard. A 1 kilogram steel mass has a different weight when measured on the moon.
So, distance from the center of the earth (yes, you do weigh less on top of Mt. Everest) and a small amount of centrifugal force (equator vs. poles), can both have a measurable effect on your weight.
However, since we are measuring weight and not mass, your weight changes significantly if you are floating in water or in some other medium where your bouyancy would have an effect.
Rephrasing your question to be, where on the surface of the earth will apparent gravity me minimized, the answer is somewhere near the North Pole.
2006-08-29 06:33:12
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answer #3
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answered by tbolling2 4
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Kalel's answer is interesting, but Promethius is right on target. He knows what he's talking about. Some of the answers are in "outer space", especially those that say you weigh more at the equator because there's "more mass" beneath your feet.
Actually, there are three things going on here. To see all of it, imagine that the spinning earth is more flattened at the poles than it is, and more bulging at the equator.
First, because the force of gravity varies as the square of the distance to the center of mass, you'd weigh at the poles because you're closer to earth's center.
Second, the centripetal force tending to make you fly off the earth (due to the earth's rotation and your distance from the axis of rotation) will increase as your distance from the axis of rotation increases. This is zero at the poles, and reaches a maximum at the equator. Note that this force, which weight, is "horizontal", directed away from the axis of rotation, not away from the earth's center of mass.
Third, imagine that you're neither at a pole, nor at the equator, but somewhere in-between, such as at 45 degrees latitude. If you resolve all the acting forces into two components -- one directed toward the axis of rotation, and the other directed towards the equatorial plane (sort of like cylindrical coordinates) -- then the latter force will be slightly greater than the former, with the effect that the earth (if it were gaseous) would tend to flatten out like a spinning pizza crust. (It wouldn't flatten out completely, because the gravitational component directed toward the axis of rotation greatly exceeds the oppositely directed centripetal force; that's why Jupiter is not flat.)
This last is the reason that the solar system is flat.
2006-08-29 06:35:04
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answer #4
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answered by bpiguy 7
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I believe it would be at the equator. The Earth is not a perfect spheroid, but rather is a bit flattened out at the poles due to its own rotation. So the equatorial diameter is greater than the polar diameter. The Earth is sufficiently large and uniform that I believe it behaves locally like a sphere with radius equal to the local radius. Since the mass of a body with uniform density increases cubically with radius, and gravity weakens with the inverse of the square of the radius, the gravitational force due to a body's mass at the body's surface increases linearally with radius. So at the point of greatest radius, in this case the equator, a person's weight is probably the greatest. (In other words, you're further from the Earth's center of mass, but there's also more mass directly under you.) Since the equatorial radius is only .34% greater at the equator than at the poles, the differences are negligible on the scale of a typical individual's weight.
2006-08-29 03:52:21
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answer #5
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answered by DavidK93 7
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Congratulations!!!!!! You asked a question and got 100% wrong answers!!!
People are confusing the shape of the earth, gravity, density of the air etc and failing to examine the defined properties of weight.
Weight on earth is measured with a number of scales but lets use the pound. A solid piece of metal is made that at a fixed position and height on earth is held to be exactly one pound. That will be the only place on earth that it will weigh exactly that but the importance is that that bilt of metal is the defined pound.
Where ever you weigh a body on earth, whether it be at the poles, in heat, in cold, below sea level or at the top of Everest. The definition of your weight that is used is the comparison between you and that same reference bilt of metal at the exact same spot you are at, at the time. It therefore cancels any difference in gravity, air density or any other variable. Those are only apparent variations and are false.
The right answer therefore can only be that you weigh exactly the same wherever you are on earth.
2006-08-29 06:10:00
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answer #6
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answered by Anonymous
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Theoretically it should be at the highest point of the equator ,depending on the distance between the body and the center of the earth ,so I supposed that this distance will be greatest at the equator,but it could be anywhere else like the mount Everest ,as I said depending on the distance to the center of the earth.
The earth is oblate spheroid ,the radius to the equator is greater than its to the poles and the gravity comes from the mass so more mass means more gravity .
2006-08-29 03:55:22
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answer #7
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answered by vivgig2001 2
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the Jennie Craig Clinic.
The answer is not so much determined by whether you are at the poles or the equator, but rather inconsistencies in the Earth's spherical shape or uniformity.
Centrifugal force also plays a role, I'm not sure how much, so maybe the poles.
2006-08-29 03:47:55
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answer #8
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answered by s_e_e 4
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It might be interesting to know the Heaviest Man instead...
The heaviest person in medical history was Jon Brower Minnoch (USA, 1941–83), who had suffered from obesity since childhood. He was 185 cm (6 ft 1 in) tall and weighed 178 kg (28 st) in 1963, 317 kg (50 st) in 1966 and 442 kg (69 st 9 lb) in September 1976.
In March 1978, Minnoch was admitted to University Hospital, Seattle, where consultant endocrinologist Dr. Robert Schwartz calculated that Minnoch must have weighed more than 635 kg (100 st), a great deal of which was water accumulation due to his congestive heart failure.
In order to get Minnoch to University Hospital, it took a dozen firemen and an improvized stretcher to move him from his home to a ferry-boat. When he arrived at the hospital, saturated with fluid and suffering from heart and respiratory failure, he was put in two beds lashed together. It took 13 people just to roll him over.
After nearly two years on a diet of 1,200 calories per day, he was discharged at 216 kg (34 st) – the greatest weight loss for a human being. In October 1981, though, he had to be readmitted – after putting on over 89 kg (34 st). When he died on September 10, 1983, he weighed more than 362 kg (57 st).
2006-08-29 03:58:43
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answer #9
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answered by cascadingrainbows 4
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I hope you are referring to the weight as in the one we take on the scales...I believe its the same everywhere as the earth's gravitonal pull is almost the same all across the planet, however slight modification on the same could be found at different places on earth but usually the differences are not more than a few grams of "weight"
2006-08-29 03:47:35
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answer #10
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answered by bostoncity_guy 2
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