A bottle contained 560g of sugar. Hui Nah used 70% of it to make coffe. How many grams of sugar did she use for making cooffe?
2006-08-29 02:04:02 · 14 answers · asked by Ghost 2 in Education & Reference ➔ Primary & Secondary Education
70% of 560g = 70/100 x 560
= 0.7 x 560g
Ans = 392g
560g is 100%. If she used only 70%, use the formula above. Notice that the word "of" becomes the mathematical "x" (multiply)
70% of something is equal to 70/100 x "something.in this case the 560g of sugar. therefore 70% = 70/100. Any number , 70%, 85%, 21%, jus used the number to divide by 100.
U can play around with it.
2006-08-29 02:12:50 · answer #1 · answered by monokye 3 · 0⤊ 1⤋
Hey man thats simple. Here you go
Since Hui used 70% of 560g, you find out what 70% of 560g is...this is how you do that'
70% = 70/100 = 0.7
0.70X560=392g
Thats your answer: 392g
2006-08-29 09:11:09 · answer #2 · answered by dog_hell_red 5 · 0⤊ 0⤋
70% = 0.70
therefore 70% of variable X is equal to 0.70 * X
the variable in your question is the sugar so
X = 560g
therefore
0.70 * 560g = 392g
she used 392 grams of sugar for her coffee :~)
2006-08-29 09:17:20 · answer #3 · answered by simchiman 2 · 1⤊ 0⤋
70% of 560g is 392g of sugar used.
2006-08-29 09:10:08 · answer #4 · answered by Answers1 6 · 0⤊ 0⤋
70% = 70/100 = 0.7
0.7 * 560 = 392
Therefore she used 392 grams of sugar.
Cheers
Singapore
2006-08-30 05:17:35 · answer #5 · answered by isz_rossi 3 · 0⤊ 0⤋
EEEEEEEEEEasy!!!!
70% is = to 0.70
70% of 560g of sugar
Therefore.
0.70 * 560g=392
2006-08-29 09:09:12 · answer #6 · answered by SweetBrunette 5 · 0⤊ 0⤋
70% of 560 gms will be 560*70/100 is the quantity used for coffee
2006-09-02 06:16:05 · answer #7 · answered by Sankaranarayanan R 2 · 0⤊ 0⤋
392 g
2006-09-02 02:06:47 · answer #8 · answered by Ana J 2 · 0⤊ 0⤋
560 * 70% (or you could mak 70% a decimal 0.70 on the calculator) And that is your answer (392)
2006-08-29 09:10:49 · answer #9 · answered by KassieB 2 · 0⤊ 0⤋
392 grams, you are left with 168 grams
2006-08-29 09:12:34 · answer #10 · answered by raineydazey 2 · 0⤊ 0⤋