How do you calculate the Thermal Equilibrium when two glasses of water are mixed?

Question

it might be zeroth first law..?!! but what is the law?

Answer 1

Calculate each glass of water before you mix,then measure it after they are mixed and note the difference.

Answer 2

Pick a temperature (0°C on the liquid side of the phase change is always good ☺) and calculate the number of Calories required to raise the mass of water in each glass to it's current temperature. Then calculate the number of calories total (glass 1 and glass 2) and use it to calculate the temperature of the total mass of water after the two glasses are mixed.


Doug

Answer 3

Glass of water contains Q1=m1*c*T1 of heat (m=mass; c=heat capacity; T=temperature in Kelvins) and the other glass Q2=m2*c*T2

The mixed glass contains Q3 = Q2+Q1 of heat.

Q3=m1*c*T1+m2*c*T2

And the temperature of the mixed glass is T=Q3/((m1+m2)*c)

Answer 4

Tfinal = T1 * v1 / (v1 + v2) + T2 * v2 / (v1 + v2)
I don't know if this is the "correct" way of putting it, but it works. (But only for problems without phase transitions, such as freezing, evaporation etc)
NOTE: T is the temperature in Kelvin! This is important. Google is your converter:
http://www.google.com/search?q=68+F+in+K and so on...

Answer 5

wight of first glass water multiply by its absulate temp , plus weight of second glass water by its absulate temp . THIS SOME IS DEVIDE BY TOTAL WEIGHT OF WATER.

Answer 6

un mix them