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Prove
tanx/n = very high

^_^

2006-08-29 00:28:08 · 6 answers · asked by kevin! 5 in Science & Mathematics Mathematics

6 answers

Yeah sure.


tan x / n = ta x

ha... ha... ha...

Try harder next time.

2006-08-29 00:31:39 · answer #1 · answered by Vincent G 7 · 4 0

The closer the tangent function is to 90 or 270, the higher it will be. At those two points, it is so high that's it's undefined. As soon as you pass them, though, the value shoots down to negative infinity, and on the way back up, it passes the value of zero. What I'm saying is, without the values of x and n, there's no telling how high or low the tangent will be.

2006-08-29 03:01:37 · answer #2 · answered by Mehoo 3 · 0 0

Your question is ambiguous. Define x and n first.

If x is the angle and n is just a number, then:

You are false.

0 <= tan (x) < [infinity] on the domain 0 <= x <= 2 pi.

Even if n = infinity, 'very high' is false because tan(Pi/2) = infinity and dividing that by n = infinity :

tan (pi/2) / infinity = 1

so the function f(x) = tan(x) / n ranges from 0 <= f(x) <= 1


Bam!

2006-08-29 03:50:55 · answer #3 · answered by ivyeurasian 1 · 0 0

n = 1/ very

tanx = high

so, tanx/n = very high

Hence proved

2006-08-29 00:31:38 · answer #4 · answered by DG 3 · 1 0

lim(n->0) tan/n = infinity

2006-08-29 03:38:51 · answer #5 · answered by Anonymous · 0 0

sry, donno

2006-08-29 01:10:25 · answer #6 · answered by bestfootballer 2 · 0 0

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