If the radius of a circle i 2m, velocity = 15 radians per second, is the time for one revolution = 5.26s? How can you calculate the centrepetal force, from this information?
2006-08-28 23:52:23 · 10 answers · asked by jeanpace89 1 in Education & Reference ➔ Homework Help
In this question, please? The calculation
2006-09-01 07:38:58 · update #1
moving or tending to move towards the centre
2006-08-31 10:37:04 · answer #1 · answered by dinkydoo 3 · 0⤊ 0⤋
The centripetal acceleration is directed toward the center of the circle, and always perpendicular to v. The force causing a centripetal acceleration acts toward the center of the circular
path and causes a change in the direction
F=m v^2/r = m r w^2
you have to know the mass or the answer be in terms of m.
r=2, w=15
2006-08-29 00:21:07 · answer #2 · answered by Mr Perfect 2 · 0⤊ 0⤋
The centripetal force is the force needed to move an object in a circle at constant speed.
The centripetal acceleration varies with the radius r of the circle and speed v, becoming larger for higher speed and smaller radius. More precisely, the centripetal acceleration is given by by equation a = w^2/r w=v/r =15/2=7.5 radians/meter
7.5*7.5=56.25 56.25/2=28.125= acceleration (square radians/meter}
In order to calculate force you need to know mass of the object and multiply it by acceleration to obtain force.
2006-09-05 10:15:23 · answer #3 · answered by Anonymous · 0⤊ 0⤋
I don't think so. My physics is shaky, but the way I understand it is:
Speed = distance over time
Time = distance over speed.
The circumference of the circle = 2 by pi by 2m = 12.566...m
If you divide this by the speed you'll get the time it takes for revolution: I'm guessing because radians are dimensionless.
12.566...m over 15 rad/s = 0.8378s for one revolution.
The centripetal acceleration is the angular velocity squared multiplied by the radius:
12.566m over 0.8378s = 15m/s:
then square that: 225
225m/s by 2m = 450 m.m/s
If you wanted the force you'd need the mass of the object. This all might be wrong but that's how my pudding brain sees it.
2006-09-02 22:12:08 · answer #4 · answered by epicure 2 · 0⤊ 0⤋
Centripetal acceleration ees impossible, ze centripetal ees ze brake petal.
2006-08-29 00:03:32 · answer #5 · answered by Anonymous · 0⤊ 0⤋
Not a clue my dear - all sounds very difficult! However, this link seems to have some papers/articles on it.
http://www.psigate.ac.uk/roads/cgi-bin/psisearch.pl?term1=centripetal+acceleration&limit=0&subject=All
I hope it is useful - and good luck!
2006-08-29 00:00:16 · answer #6 · answered by peggy*moo 5 · 0⤊ 0⤋
it can sometime be called tangential accelaration. use the usaul force formular to calculate force, not gonna give you much! u r on the right track.
2006-08-29 00:02:11 · answer #7 · answered by kau la poo 2 · 0⤊ 0⤋
I would probably find someone who knows what the hell you are talking about and ask them to calculate it for me.
2006-09-05 20:21:24 · answer #8 · answered by Anonymous · 0⤊ 0⤋
A quick glance at this page should help... http://en.wikipedia.org/wiki/Centripetal_force
2006-08-28 23:58:22 · answer #9 · answered by Lord Grover 2 · 0⤊ 0⤋
I wish i knew.
2006-08-29 00:02:40 · answer #10 · answered by Dazman 3 · 0⤊ 0⤋