Can somebody tell me if i did this algebra question right? please?

Question

1/3(x-2)=2/3x - 13/3

6/3x - 6/6= 2(6)/3x - 13(6)

2x - 1 = 4x - 26

2x - 4x = 1-26

-2x = -25

x = -25/-2

??????????

Answer 1

OMG.. Okay first multiply the 1/3 into the (x-2) so that will be 1/3x-2/3. X's like to go with their own kind.

Once the parenthesis is gone...

add/subtract/divide/multiply their coefficients and keep the x still attached to them like a hat.

Then add or multiply etc...etc.. the numbers like in preagebra.

Then multiply,divide the coefficient to the other side and you'll have x =...number/fraction

Only listen to zzzlordcharm if you REALLY meant 2/3x and not 2/3*x. I doubt that is the case cause they wouldn't have you doing quadratic formulas if you can't even deal with multiplying 1st degree variables with coefficients. Its funny how he took all that time.

Answer 2

The answer is not -25/2.
Neither is it 11.

The question is 1/3(x-2)= 2/3x - 13/3

Now, on the Right Hand Side (RHS), the 'x' is with 3, and not with 2.

Ok, here' s what to do:

First, open the parenthisis of the LHS, you'll have
x/3 - 2/3 = 2/3x - 13/3.

Now, collect all the 'x' together, and thee ones without x, u'll have

x/3 - 2/3x =2/3 - 13/3.
Now, we split it into 2. Let's do the LHS first.

x/3 - 2/3x. The common denominator is 3x; therefore,
x^2/3x - 2/3x.
Since they both have the same denominator, we can put them together as
(x^2 - 2) /3x
Now, we do the RHS.
2/3 - 13/3 = -11/3

Putting LHS and RHS together, we have,

(x^2 - 2)/ 3x = -11/3

Now, whenever you have two fractions separated by an equal sign, you can always cross-multiply. Therefore,

3x^2 - 6 = -33x.

Bringing -33x to join the LHS family, you'll have

3x^2 + 33x - 6 = 0.

This is clearly a quadratic equation.
Using the quadratic formula,
x = [-b + - sqrt (b^2 - 4ac)]/2a

a= 3, b = 33, c = -6; therefore, we have

x = [-33 + - sqrt(1089 + 72)] / 6

x = [-33 + 3 x sqrt 129]/6, x = [-33 - 3 x sqrt 129]/6.

You'll have two answers and they'll only be approximations unless choose to leave them in fractional forms, in which u'll have

x = [-11 + sqrt 129]/2, x = [-11 x sqrt 129] / 2

Too long, and not as explanatory as I wanted, but that's the answer.

Answer 3

I'm sorry, but if I understood your original equation correctly, you did not. Your first mistake was in multiplying everything by 6. You didn't need to do this. Let's start over:

1/3 *(x-2) = 2/3 * x -13/3

There are a couple ways you can attack this problem. I would first try to get rid of the fractions by multiplying each side by the lowest common denominator, i.e. "3":

x-2 = 2x - 13

Now move all x's to one side and all integers to the other by subtracting 2x and adding 2:

-x = -11

Get rid of the negative by multiplying by (-1):

x = 11

If you meant to have the x's in the denominator of the equations, let me know and I'll redo the explanation for you. I hope this helps!

Answer 4

you need to clarify your equation. It is not clear which variables or numbers are in the denominator. For example, the first term as you have written it: 1/3(x-2). Does this mean one third of the quantity (x-2) or does it mean 1 divided by the product of 3 and (x-2)?

Answer 5

ok. i understand that various of the solutions are superb and your answer is incorrect. a thank you to think of of that's the great device does a million/12 of the blend in a million hour and the small device does a million/20 of the blend in a million hour. So in case you upload those jointly and multiply with the help of x hours to get a million finished blend the equation appears like this (a million/12 + a million/20)*x = a million Now, you may multiply all words of the equation with the help of a hundred and twenty to get (10 + 6)*x = a hundred and twenty and fixing for x components 7.5 hours. in case you do those issues making use of this technique they are lots much less complicated to establish and clean up.

Answer 6

itz wrong.

an easier way 2 chk wether ur answer is correct or not is to put the value of x wich u get in the ques. if both sides r equal ur ans is correct.

da soln.
1/3(x-2)=2/3x - 13/3
multiply thru out by 3
u get
x-2 = 2x-13 ? isnt it
now we get
13-2=2x-x
therefore x=11

nbow to chk wether it is correct put x=11 in the ques. if both sides are equal itz correct

Answer 7

wrong, you should have multiplied it by 3 which gives

x - 2 = 2/x - 13

x - 2 = (2 - 13x)/x

multiply all by x

x^2 - 2x = 2 - 13x

x^2 + 9x - 2 = 0

sorry, i misplced the x in the question. i thought it's 2/3x but its 2x/3.

Answer 8

*Wow the people above did it the long way*

Multiply both sides by 3
--> x-2= 2x -13
Get x's on one side and numbers on the other
--> -x= -11
Now Divide each side by -1
--> x= 11

*And you get the answer in 3 steps :D *

Answer 9

wrong

x = 11

it's pretty straightforward:
- multiply both sides by 3, you get
x - 2 = 2x - 13
- subtract x from both sides, you get
-2 = x - 13
- add 13 to both sides, you get
11 = x

hope this helps

a

Answer 10

Frankly, forget about this question and algebra. Go backward and relearn properly your basic arithmetic!