Can you please help me with this word problem?

Question

Joy has a solution containing 12% alcohol. How much of this solution and how much water must she use to get 6 liters of a solution containing 10% alocohol?

Answer 1

say her original amount she has is x litres.

of this 0.12x is alcohol
and 0.88x is water (that's how you get 12% strength alcohol)

She wants 6 l mixture with
0.6 litres alcohol
and 5.4 litre water

Therfore she should add 0.6 - 0.12x liters alcohol
and 5.4 - 0.88x liters water.

IF you know x (the original amount of mixture in liters) you can plug it in and get numbers.

Hope this helps

Answer 2

Blind chameleon is right.
The new alcohol content is 0.6 L and the new water content is 5.4 L . To know how much water was mixed with how much alcohol, there must be an initial amount of the mixture that we need to know of; otherwise, the answer would be in a variable form.

On the other hand, the question kinda seems not alright. Even if the initial amount of the mixture is known, since the volume of the alcohol and the water is both changing(usually, one of them, usually the alcohol, must be constant), it would require another equation to finally resolve the final answer.

But all Maths and no sleep, makes someone a crazy man

Answer 3

to get a 6 litre souldution containg 10% alcohol
we have to say the ammount of alcohol = 0.6 L
to provide 0.6 L of alchohol out of the soulution we have (12%) we'll need
0.6 / 0.12 = 5 litres
so the solution will contain 5L of the12% solution + 1L of water
to check....

5 litres of the 12% solution contains...
0.12*5 = 0.6L of alchohol

so no need to know the original quantity of the solution as in the first answer

Answer 4

maybe chemist can answer this

Answer 5

i knew dis type.... but i frgot