ABCD is a quadrilateral with AB = 2,BC = 2,angle(ABC) = 104 and angle(ADC)=132.Find the length of BD.
2006-08-28 17:38:08 · 6 answers · asked by Rohit C 3 in Science & Mathematics ➔ Mathematics
BD=1.957
2006-08-28 18:33:58 · answer #1 · answered by Oh Yeah! 2 · 0⤊ 1⤋
This question is not clear enough. In other words, there are several answers for this question. In the triangle ABC you have the lent of AB and BC and you have the angle between them, the angle ABC, as well. So you can calculate the Lent of AC. Then in triangle ADC you have the Lent of AC and the angle in front of it. there are several triangles which have the same Lent of AC and the same ADC angle. It means that the point of D can be in many different positions. So these are not enough to calculate the Lent of BD.
2006-08-28 18:58:45 · answer #2 · answered by Arash 3 · 0⤊ 0⤋
you cannot definite a quadrilateral with less than 5 factors, whereas there're only 4 here.
the length of BD can be anything from 1.933 up to 2
2006-08-28 21:14:46 · answer #3 · answered by magicmoonha 2 · 0⤊ 0⤋
BD=1.957
2006-08-29 02:42:11 · answer #4 · answered by radioconcrete 2 · 0⤊ 0⤋
1.96
2006-08-28 19:06:15 · answer #5 · answered by Mr. Logic 3 · 0⤊ 0⤋
This is really a tough one.
2006-08-28 19:06:51 · answer #6 · answered by female_lizzzzzard 3 · 0⤊ 0⤋