A consultant traveled 9 hours on her way to a meeting. The return trip took 8 hours because the speed was 4 mph faster. What was her speed each way?
2006-08-28 16:31:14 · 6 answers · asked by badbullit518 1 in Science & Mathematics ➔ Mathematics
8*(4+X) = 9X
32 + 8 X = 9X
X=32
sO the speed is 32 mph and 36 mph
2006-08-28 16:36:07 · answer #1 · answered by ArcherOmega 4 · 0⤊ 0⤋
32 36
2006-08-29 00:19:57 · answer #2 · answered by keep~it~real 3 · 0⤊ 0⤋
v=d/(9 hours)
v+4 mph=d/(8 hours)
Solving the second equation for distance:
8v hours + 32 miles=d
Substituting:
v=(8v hours + 32 miles)/(9 hours)
simplifying:
v=8/9v + 32/9 mph
1/9v=32/9 mph
v=32 mph
Thus her speed to the meeting was 32 mph and from the meeting it was 36 mph.
2006-08-28 23:38:40 · answer #3 · answered by Pascal 7 · 1⤊ 0⤋
Let r = speed
d = fixed distance
d = rt, so
d = (r)(9 hr) and
d = (r + 4 mi/hr)(8 hr)
Use the transitive property
r(9 hr) = (r + 4 mi/hr)(8 hr)
Remove the hr unit
r(9) = (r + 4 mi/hr)(8)
distribute
9r = 8r + 32 mi/hr
Transpose and subtract
r = 32 mi/hr
The other speed is
r + 4 mi/hr = 36 mi/hr
Therefore, the speed to the meeting is 32 mi/hr and the return trip speed is 36 mi/hr.
^_^
2006-08-29 07:53:14 · answer #4 · answered by kevin! 5 · 0⤊ 0⤋
9x = 8(x + 4)
9x = 8x + 32
x = 32
She went 32 mph to the meeting and 36 mph from the meeting.
2006-08-28 23:38:18 · answer #5 · answered by jimbob 6 · 1⤊ 0⤋
Are you serious?
Do you take us for a chump, chump?
Just by labeling your homework as "Math Riddle" you think that you are going to trick us here into doing your homework for you.
2006-08-28 23:34:33 · answer #6 · answered by The Prince 6 · 0⤊ 1⤋