what is the x-int, y-int and the turning point?

Question

f(x) = (x-1) ^ 2

would the x-int be 1? and how do you figure out the y-int? and should the turning point be 1 as well? since the degree in this equation is 2 and you subtract 1 from the highest exponent. thanks for the help.

Answer 1

x-int=1

y-int=(0-1)^2
y-int=(-1)^2
y-int=1

turning point= (1,0)

Answer 2

Yes the x-int is 1 and so the y-int.
The turning point also 1.

Answer 3

X-int is 1, yes.

For y-int, let x=0, so y = (0-1)^2 = 1

Turning point is (1,0), the vertex of the parabola.