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the point (11,0).

2006-08-28 14:30:03 · 5 answers · asked by Anonymous in Science & Mathematics Mathematics

from the point (11,0)

2006-08-28 14:40:49 · update #1

Find the point above the x-axis on the circle of radius 11 centered at (0,0) that is 10 units away from?
the point (11,0)

2006-08-28 14:42:18 · update #2

5 answers

use the pythagorean theorem:

10^2+x^2=11^2
x=(121-100)^.5
x=4.58

2006-08-28 14:53:04 · answer #1 · answered by zmonte 3 · 0 0

IF I understand correctly, you are asking for the point on the circle x²+y²=121 that is 10 units away from {11,0}

OK. The set of all points that are 10 units away from {11,0} form a circle whose equation is (x-11)²+y²=100

Solve the two quadratics simultaneously (for positive y values, there is a 'mirror image' point 'below' the x axis) and you have your answer.


Doug

2006-08-28 14:48:03 · answer #2 · answered by doug_donaghue 7 · 0 0

because of the fact the centre of circle would be above the factor (5,0). for this reason, x-coordinate would be comparable i.e., 5. for y-coordinate, the radius is 6. So, y-coordinate would be 6. So the centre is at (5,6)

2016-11-05 23:58:09 · answer #3 · answered by ? 4 · 0 0

You can solve this problem by your Algebra.

2006-08-28 14:53:42 · answer #4 · answered by ArcherOmega 4 · 0 0

ten units away from what?

2006-08-28 14:36:39 · answer #5 · answered by Chrissy F 1 · 0 0

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