It does sound rather odd, doesn't it? I would just draw a circumcircle, or six of them...
2006-08-28 14:20:28
·
answer #1
·
answered by Justsyd 7
·
0⤊
1⤋
1
6 4
3 2 5
2006-08-28 14:24:43
·
answer #2
·
answered by Jill&Justin 5
·
0⤊
1⤋
3
6 2
1 4 5
2006-08-28 14:22:13
·
answer #3
·
answered by bandido 4
·
0⤊
1⤋
1
6 4
3 2 5
Let me tell you how I did it. first I know that 5 and 6 could not be in the same row. I then figured that 2, 3, 5 and 1, 4, 5 had to be in the same row. From there it fell into place.
2006-08-28 14:29:01
·
answer #4
·
answered by gtn 3
·
0⤊
0⤋
1
64
325
just draw one circle on the 1st line
2 circles on the second line
and 3 on the 3rd line, so that they form a triangle and then enter the numbers 1-6 in the same order I have listed above and when you add the sides they equal to 10
2006-08-28 14:22:09
·
answer #5
·
answered by ratel 3
·
1⤊
1⤋
work through each line thinking carefully
line one 1
linetwo 4 6
line three 5 2 3
there u go remember don't get too excited and tell him the answer just help him figure it out on his own
2006-08-28 14:26:07
·
answer #6
·
answered by Anonymous
·
0⤊
0⤋
Ignoring each and each of the jokey solutions and the very incontrovertible reality that a cylinder is a three-d merchandise, i have had a nosey around the internet and the nearest difficulty i'll go back up with to what you're describing is a "Cassini oval". The link's below - see what you imagine. nicely performed to Puffy Brown Rabit (sic) - did not see that one!
2016-11-28 03:28:50
·
answer #7
·
answered by hinnant 4
·
0⤊
0⤋
alright i think i have it.
1
4 6
5 2 3
i hope this helped!!!
2006-08-28 14:24:23
·
answer #8
·
answered by um yea hi 4
·
0⤊
1⤋
X
XX
XXX
You have 3 circles to a side. (/_\)
The answer:
5
42
163
2006-08-28 14:23:34
·
answer #9
·
answered by Illy 3
·
0⤊
1⤋
side 1 - 1 6 3
side 2 - 3 2 5
side 3 - 5 4 1
.......1
....6......4
.3.....2.....5
2006-08-28 14:23:40
·
answer #10
·
answered by Gehan G 3
·
0⤊
1⤋