2006-08-28 13:27:25 · 5 answers · asked by Oneal2B 1 in Education & Reference ➔ Words & Wordplay
11 sets of slippers for cats. Cats have four feet. 4x11=44
43 sets of slippers for bats. Bats have two feet. 2x43=86
This is not exactly twice as many, however, but the total is 130...
Perhaps this question involves fractions? Any one legged cats?
The other way to look at it would be to say that the 130 slippers are divided evenly (65/65) between the cats and bats, but the bats, having half as many legs as the cats, therefore have twice the number of slipper "sets". ???
2006-08-28 16:31:03 · answer #1 · answered by livysmom27 5 · 1⤊ 0⤋
86 bats and 43 cats
2006-08-28 21:38:11 · answer #2 · answered by tazzgirl6983 2 · 0⤊ 0⤋
This problem has no answer (unless a fraction of a slipper counts). Not every math problem has an answer.
2006-08-28 20:35:20 · answer #3 · answered by Anonymous · 0⤊ 0⤋
well duh there are going to be twice as many slippers for cats than bats cuz cats have more feet...so its gonna be a fraction
c-cats
c+2c=130
c+2c=3c so 3c=130
130/3=about 43 1/3 for cats and twice that many for bats
2006-09-01 17:36:29 · answer #4 · answered by ChubbyCheeks 2 · 0⤊ 0⤋
c = cats
b = 2(c)
c + 2c = 130
3c = 130
weird question..but it's gonna be fractions pretty much
2006-08-28 20:35:34 · answer #5 · answered by sasmallworld 6 · 0⤊ 1⤋