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why does every number raised to the power of 0 =1?

2006-08-28 13:13:57 · 6 answers · asked by Anonymous in Education & Reference Homework Help

6 answers

To divide powers, you subtract the exponents. For example, 3^7 / 3^5 = 3^(7-5) = 3 ^ 2 =9.
Therefore, x^a / x^a = x ^(a-a) = x^0
But anything divided by itself is 1, therefore x^a/x^a = 1
Since x^a/x^a = X^0 = 1, X^0 =1

2006-08-28 13:21:41 · answer #1 · answered by Goddess of Grammar 7 · 1 0

Any number, except 0, raised to the zero power always equals 1.

2^1 = 2
2^0 = (2/2) = 1

2006-08-28 20:19:32 · answer #2 · answered by Anonymous · 0 0

Powers are always multiplied by 1 first.

2^3 = 1 * 2 * 2 * 2

2^2 = 1 * 2 * 2

2^1 = 1 * 2

2^0 = 1

2006-08-28 20:23:32 · answer #3 · answered by Elim 5 · 1 0

As the exponent rises, you multiply the number with it's base number, so, as it decreases you divide the number with it's base number.

2^5=32......3^5=243
2^4=16......3^4=81
2^3=8........3^3=27
2^2=4........3^2=9
2^1=2........3^1=3
2^0=1........3^0=1

You can see a pattern here.

32/2=16, 16/2=8, 8/2=4, 4/2=2, 2/2=1

243/3=81, 81/3=27, 27/3=9, 9/3=3, 3/3=1

2006-08-28 20:22:41 · answer #4 · answered by Anonymous · 0 0

because it is multiplied by itself 0 times.

if it were equal to 0 then

5 times (20 to the power of 0) would equal to 0.

It just is

2006-08-28 20:18:13 · answer #5 · answered by doc2be 4 · 0 0

Thats one of those unanswerable questions

2006-08-28 20:16:36 · answer #6 · answered by Sarah 2 · 0 1

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