word problem-water in a lake?

Question

a lake covers 928 acres w/ an avg depth of 17 ft. estimate the # of cubic feet of water in the lake. if 1 cubic ft = 7.48 gallons, approximate the # of gallons of water in the lake.

i know i have to convert using 1 acre=43,560 squared ft.
thanks for the help.

Answer 1

To answer this problem, we want to calculate the volume of the lake, (here, volume is equal to the depth multiplied by the area of the lake), with our given information. We know that the lake is 928 acres. Let's convert those acres to feet squared:

(928 acres)*(43,560 sqft)=40,423,680 sqft

Now, we know the area of the lake. Next, we can do this by multiplying the square footage of the lake by the average depth of the lake:

(40,423,680 sqft)*(17 ft)= 687,202,560 cu ft

We have calculated the volume of the lake in cubic feet. We can now calculate the number of gallons of water in the lake:

(687,202,560 cu ft)*(7.48 gallons/1 cu ft)= 5,140,275,148.8 gallons of water.

Hope this helps.

Answer 2

928 Acres x 43,560 Square feet per Acre =
40,423,680 total Square feet.

40,423,680 total Square feet x 17 Feet Deep =
687,202,560 total cubic feet of volume in the lake

687,202,560 total cubic feet x 7.48 gallons per cubic foot =
5,140,275,149 total gallons of water in the lake

Answer 3

So, there are 928*17 acre-feet. So there are 43,560*928*17 cubic feet. So there are 7.48*43,560*928*17 gallons. Approximately? Call it 8*40,000*1000*20 or 6,400,000,000 gallons.

Answer 4

Your aim is to find the volume of water in the lake

First convert area of the lake form acres to sq ft:
928 acres x (43560 sq ft/ 1acre) = 40423680 sq ft

Now find the volume of the lake by multiplying area by depth:
(40423680 sq ft) x (17 ft) = 687202560 cubic ft.

Now convert volume from cubic feet to gallons:
(687202560 cubic ft) x (7.48 gal/ 1 cubic ft)
= 5140275148.8 gallons or 5.14 x 10e9 gallons

Answer 5

volume=area*height=938*43,560*17 cft
=938*43,560*17*7.48 gallons=5195666044 gallons