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A rectangle has a length of 2d and a height of d. Each of the following three charges is located at a corner of the rectangle: +q1 (upper left corner), +q2 (lower right corner), and -q (lower left corner). The net electric field at the (empty) upper right corner is zero. Find the magnitudes of q1 and q2. Express your answers in terms of q.

2006-08-28 08:07:54 · 2 answers · asked by Nyto 1 in Science & Mathematics Physics

2 answers

Interesting...

Given that Ex at (2d, d)=0

E=F/q=k(Q/R^2)
Ex=E1+E2+E3=
=k(q1/(4d^2) + q2/(5d^2) - q3/d^2))=
Then we have
(k/d^2)(q1/4+q2/5-q3)=0

Or

Q1/4+2q2/5-q3=0 then

q=q3=(4q1+5q2)/20

if q1=q2

then q1=q2=20q/9=2.2q

I hope that helps.

2006-08-28 09:50:14 · answer #1 · answered by Edward 7 · 0 0

A

2006-08-28 08:12:43 · answer #2 · answered by Richard N 2 · 0 0

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