Here is your correct answer,please look at what I've done carefully.
(d/dx)
sin(x) = cos(x)
&
cos(x) = - sin(x)
as i said before
{ well its what we have f(x) = 2sin x cot x - 2cos x tan x ,you should try to simplify f(x),How? i will tell you now
cotx = cosx / Sinx
tanx = Sinx / Cosx
Step 1 ;
2 ( sinx ( cosx / Sinx )) - 2( cosx ( Sinx / Cosx)) , now in the first decimal you can remove " sinx " and in the second decimal you can remove " cosx " , Therefore we have
2 Cosx - 2 Sinx
Step 2 ;
just factor " +2 "
so we have
2 ( Cosx - Sinx )
now if we have the value of " x " we can put it in this function and get the result.}
now f(x) =2 * ( Cosx - Sinx )
{ remember if f(x) =a and ' a " is a real number Derivative f(x) = 0 so Derivative 2 = 0 }
Derivative f(x)
or
f '(x) = 0* [(-sin(x)) - cos(x)] = 0
f '(x) = 0
Good Luck Friend.
2006-08-28 13:28:16
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answer #1
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answered by sweetie 5
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tan x + sec x = 2cos x sin/cos + a million/cos = 2cos sin + a million = 2 cos² sin + a million = 2( a million - sin²) sin + a million = 2 - 2sin² 2sin² + sin - a million = 0 (2sin - a million)(sin + a million) = 0 sin x = a million/2, x = ?/6 or x = 5?/6 sin x = -a million, x = 3?/2
2016-11-28 02:38:52
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answer #2
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answered by ? 4
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1. cot x = cos x / sin x and tan x = sin x / cos x
2. 2 sin x cot x = 2 sin x * cos x / sin x = 2cos x
3. 2cos x tan x = 2cos x * sin x / cos x = 2sin x
4. by substitution:
f(x) = 2 cos x - 2 sin x
5. get the derivative:
d(2 cos x) = 2sin x dx
d(2 sin x) = -2cos x dx
finally:
d(f(x)) = (2 sin x + 2 cos x) dx
2006-08-28 06:10:07
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answer #3
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answered by dennis_d_wurm 4
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First simplify it using
tan x=sin x/cos x
and
cot x=cos x/sin x
to find that f(x)=2cos x -2 sin x.
The derivative is then
f'(x)=-2sin x -2 cos x.
2006-08-28 05:50:45
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answer #4
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answered by mathematician 7
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i suppose then
can be done in parts
1st
2 goes out
product rule
f'g + f g'
2(cosxcotx + sinx(deriv. of cotx) - 2(-sinxtanx + cosx(deriv of tanx)
then thats probably some sort of identity
2006-08-28 05:50:17
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answer #5
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answered by jasonalwaysready 4
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f(x)=2sinxcotx-2cosxtanx
first simplify
=2cosx-2sinx
f'(x) of a sum is the sum of the individual derivatives
f'(x)=-2sinx-2cosx
2006-08-28 06:14:10
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answer #6
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answered by raj 7
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