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2006-08-28 05:34:01 · 6 answers · asked by thegame1083 1 in Science & Mathematics Mathematics

6 answers

Here is your correct answer,please look at what I've done carefully.

(d/dx)
sin(x) = cos(x)
&
cos(x) = - sin(x)

as i said before

{ well its what we have f(x) = 2sin x cot x - 2cos x tan x ,you should try to simplify f(x),How? i will tell you now

cotx = cosx / Sinx
tanx = Sinx / Cosx
Step 1 ;
2 ( sinx ( cosx / Sinx )) - 2( cosx ( Sinx / Cosx)) , now in the first decimal you can remove " sinx " and in the second decimal you can remove " cosx " , Therefore we have
2 Cosx - 2 Sinx

Step 2 ;
just factor " +2 "
so we have
2 ( Cosx - Sinx )
now if we have the value of " x " we can put it in this function and get the result.}

now f(x) =2 * ( Cosx - Sinx )
{ remember if f(x) =a and ' a " is a real number Derivative f(x) = 0 so Derivative 2 = 0 }
Derivative f(x)
or
f '(x) = 0* [(-sin(x)) - cos(x)] = 0
f '(x) = 0

Good Luck Friend.

2006-08-28 13:28:16 · answer #1 · answered by sweetie 5 · 1 1

tan x + sec x = 2cos x sin/cos + a million/cos = 2cos sin + a million = 2 cos² sin + a million = 2( a million - sin²) sin + a million = 2 - 2sin² 2sin² + sin - a million = 0 (2sin - a million)(sin + a million) = 0 sin x = a million/2, x = ?/6 or x = 5?/6 sin x = -a million, x = 3?/2

2016-11-28 02:38:52 · answer #2 · answered by ? 4 · 0 0

1. cot x = cos x / sin x and tan x = sin x / cos x

2. 2 sin x cot x = 2 sin x * cos x / sin x = 2cos x

3. 2cos x tan x = 2cos x * sin x / cos x = 2sin x

4. by substitution:

f(x) = 2 cos x - 2 sin x

5. get the derivative:

d(2 cos x) = 2sin x dx

d(2 sin x) = -2cos x dx

finally:

d(f(x)) = (2 sin x + 2 cos x) dx

2006-08-28 06:10:07 · answer #3 · answered by dennis_d_wurm 4 · 0 1

First simplify it using
tan x=sin x/cos x
and
cot x=cos x/sin x
to find that f(x)=2cos x -2 sin x.
The derivative is then
f'(x)=-2sin x -2 cos x.

2006-08-28 05:50:45 · answer #4 · answered by mathematician 7 · 1 0

i suppose then

can be done in parts

1st
2 goes out
product rule
f'g + f g'
2(cosxcotx + sinx(deriv. of cotx) - 2(-sinxtanx + cosx(deriv of tanx)

then thats probably some sort of identity

2006-08-28 05:50:17 · answer #5 · answered by jasonalwaysready 4 · 0 1

f(x)=2sinxcotx-2cosxtanx
first simplify
=2cosx-2sinx
f'(x) of a sum is the sum of the individual derivatives
f'(x)=-2sinx-2cosx

2006-08-28 06:14:10 · answer #6 · answered by raj 7 · 0 0

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