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Not at all. Only salts from a strong base (like NaOH) and a strong acid (like HCl) form neutral solutions. Salts from a weak base and a strong acid form acidic solutions (since the weak base ion subtracts OH- ions from water); and salts from a weak acid and a strong base form basic solutions (since the weak acid subtracts H+ ions from water).

2006-08-28 04:03:37 · answer #1 · answered by ascaniosobrero 3 · 0 1

No. Some salts may contain the conjugate base of a weak acid, or the conjugate acid of a weak base.

Take Ammonium Chloride for eaxample (NH4Cl). NH4 is the conjugate acid of ammonia (NH3) which is a weak base (Kb = 1.8 x 10^-5) So after the NH4Cl dissolves, the ammonia will donate some protons to the solution to make it slightly acidic:

[NH4]+ + H2O <==> [H3O]+ + NH3

The Cl ions do not have an affect on the pH since they are the conjugate base of a strong acid.

Now look at something like sodium cyanate (NaCN). Sodium has no acid qualities since it is an alkali metal (grp I). But cyanate is the conjugate base of Hydrocyanic Acid, a weak acid (Ka = 6.2 x 10^-10). So after the NaCN salt dissolves, [CN]- ions will steal protons from the water, making the solution basic:

[CN]- + H2O <==> HCN + [OH]-

2006-08-28 13:20:37 · answer #2 · answered by Duluth06ChE 3 · 0 1

No some are acidic salts when they have an H in th formula, and some are basic if they contain an OH in the formula. It also depends on if the metal ion is very active such as Na, which can make a basic salt with a weak acid, and if the metal is weak with a strong acid for neutralization will make an acidic salt.

2006-08-28 11:15:12 · answer #3 · answered by science teacher 7 · 0 1

NO some donate H+ and form acid in the solvents and others donate OH- and make the resulting solvent more alkaline

2006-08-28 11:05:56 · answer #4 · answered by loligo1 6 · 0 1

nope. some are acidic in nature. others are basic depending on what they are composed of. ammonium chloride is acidic for example

2006-08-28 23:05:56 · answer #5 · answered by shiara_blade 6 · 0 1

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