ABCD is a quadrilateral with AB = 2,BC = 2,angle(ABC) = 104 and angle(ADC) =132.Find the length of BD.?

Question

ABCD is a quadrilateral with AB = 2,BC = 2,angle(ABC) = 104 and angle(ADC) =132.Find the length of BD.

Answer 1

IN ABCD DIAGONALS AC AND BD INTERSECTS AT O.
SO THAT BD=BO+OD.
IN TRIANGLE OAB,
COS THETA=BO/2
2*COS 52=BO
BO=1.23.................................(1)
IN TRIANGLE AOD,
TAN THETA=2/OD
TAN 66 =2/OD
OD=2/TAN66=.89..................(2)
BO+OD=BD=1.23+0.89=2.12

Answer 2

I don't see enough information to be able to solve this problem as stated. Without lengths AD or CD, or without the measure of another angle without D as a vertex, D could lie pretty much anywhere (depending on angle CAD or ACD), and BD is impossible to find.

Answer 3

1.9698