This Problem can be solved with the distance formula
d = √x2 - x1)² + y2 - y1)²
d = √(3 - 0)² + (2 - 1)²
D = √(3)² + (1)²
d = √9 + 1
d = √10
d = ± 3.16227766
d = ± 3.16 rounded to two decimal points
2006-08-28 01:00:56
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answer #1
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answered by SAMUEL D 7
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use pythogoras theoram
3-0 = 3
2-1 = 1
3^2 + 1^2 = 9 + 1 = 10 ( find its square root )
= 3.16
2006-08-28 05:23:17
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answer #2
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answered by time-OUT 4
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PQ ^2 = (0 - 3)^2 + (1 - 2)^2
= 9 + 1
= 10
Therefore PQ = sq. root of 10
2006-08-28 05:33:08
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answer #3
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answered by Anonymous
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3.16 units
square root of (3-0)^2 + (2-1)^2
^ = raised to the power of
2006-08-28 05:18:53
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answer #4
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answered by Cavallino 1
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use the distance formula
d^2 = (x1-x2)^2+(y1-y2)^2
= (3-0)^2+(2-1)^2
= 9+1 = 10
so d = Sqrt(10)
2006-08-28 05:52:20
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answer #5
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answered by Mein Hoon Na 7
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The distance is P-Q or (3,1) if you measure it in coordinates.
If you want the distance in terms of a straight line you've got a lot of answers... sqrt of 10 or 3.16
2006-08-28 05:18:58
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answer #6
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answered by virgilio costa 3
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the root of 10
2006-08-28 05:21:48
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answer #7
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answered by Anonymous
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If P means Prince ( me) & Q means Queen (You) then the distance should be 3.16 Micro mm.
2006-08-28 06:04:00
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answer #8
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answered by abhi 3
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