Jim can fill a pool carrying bucks of water in 30 minutes. Sue can do the same job in 45 minutes. Tony can do the same job in 1 ½ hours. How quickly can all three fill the pool together?
2006-08-27 18:51:40 · 6 answers · asked by Anonymous in Education & Reference ➔ Homework Help
1-minute work of John=1/30
1-minute work of Sue=1/45
1-minute work of Tony=1/90(1 & 1/2 hrs=90 mins)
Adding them ,we get
1-minute work of(John+Sue+Tony)=1/30+1/45+1/90
=6/90=1/15
So,the trio can finish the work in 15 minutes.(ANS.)
2006-08-27 19:19:08 · answer #1 · answered by Anonymous · 0⤊ 1⤋
15 minutes
In 90 minutes:
Jim can do the job 3 times.
Sue can do the job 2 times.
Tony can do the job 1 time.
Together, all 3 can do the job 6 times in 90 minutes. 90/6=15.
2006-08-28 01:55:18 · answer #2 · answered by Master Maverick 6 · 1⤊ 0⤋
Let's say it takes 30 gallons. Jim = 1 gal/min. Sue= .666 gal/min. Tony=.333 gal/min. Sue+Tony=1 gal/min. 1 gal/min + 1 gal/min = 2 gal/min. 30/2 = 15, so 15 minutes.
2006-08-28 01:56:33 · answer #3 · answered by dudefungame 2 · 0⤊ 0⤋
15 min
2006-08-28 02:07:54 · answer #4 · answered by usman 3 · 0⤊ 0⤋
5 Min.
2006-08-28 01:55:30 · answer #5 · answered by Anonymous · 0⤊ 0⤋
in 0.91 hours
2006-08-28 01:56:55 · answer #6 · answered by Anonymous · 0⤊ 0⤋