2006-08-27 18:40:54 · 19 answers · asked by shamsheer a 1 in Science & Mathematics ➔ Mathematics
1 2 and 3
2006-08-27 18:43:52 · answer #1 · answered by Anonymous · 1⤊ 0⤋
1, 2, and 3
2006-08-28 01:48:41 · answer #2 · answered by R B 1 · 0⤊ 0⤋
the numbers are:
1, 2, and 3
1*2*3=6
1+2+3=6
2006-08-28 01:44:39 · answer #3 · answered by brooke 2 · 1⤊ 0⤋
1*2*3=6
1+2+3=6
2006-08-28 01:43:46 · answer #4 · answered by Joboo 2 · 1⤊ 0⤋
1, 2, 3.
2006-08-28 01:43:57 · answer #5 · answered by Anonymous · 1⤊ 0⤋
-1 0 1
-1*0*1=0
-1+0+1=0
2006-08-28 01:51:00 · answer #6 · answered by specal k 5 · 0⤊ 0⤋
There are actually three possible answers:
1, 2, 3 (already given)
-3, -2, -1
-1, 0, 1
These are the only three possible answers. To find them, let x be the middle term of the three. Then:
(x-1)(x)(x+1)=(x-1)+x+(x+1)
x³-x=3x
x³-4x=0
x(x²-4)=0
x(x-2)(x+2)=0
Which corresponds to possible middle terms of 0, 2, and -2, respectively.
2006-08-28 04:39:17 · answer #7 · answered by Pascal 7 · 0⤊ 0⤋
123
2006-08-28 01:44:18 · answer #8 · answered by usman 3 · 1⤊ 0⤋
ans is 1,2,3 or -1,0,1,or -1,-2,-3
solution
let they be x-1,.x ,x+1
sum = 3x
product = x(x-1)(x+1) = 3x
so x= 0 or
(x-1)(x+1) = 3
or x^2-1 = 3
so x^2 = 4
so x = +/- 2
this gives 3 set of solutions
2006-08-28 05:58:31 · answer #9 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
0,1 and 2
0 x 1 = 0
2 x 1= 2
1x1= 1
2006-08-28 01:44:46 · answer #10 · answered by Leo M 4 · 0⤊ 1⤋