A hardware store sells numerals for house numbers. It has large quantities of the numerals 3,5, and 8 but no other numerals. How many different house numbers, with no more than three digits, can be made from these numerals?
2006-08-27 17:44:17 · 9 answers · asked by Peridot 6 in Science & Mathematics ➔ Mathematics
There are a total of 39 possibilities:
333, 335, 338, 353, 355, 358, 383, 385, 388, 533, 535, 538, 553, 555, 558, 583, 585, 588, 833, 835, 838, 853, 855, 858, 883, 885, 888, 3, 33, 35, 38, 5, 53, 55, 58, 8, 83, 85, and 88
2006-08-27 17:51:26 · answer #1 · answered by Sam Horner 1 · 3⤊ 0⤋
15
2006-08-28 00:53:08 · answer #2 · answered by salsa 4 · 0⤊ 0⤋
The full answer:
3 numbers with 1 digit.
9 no. with 2 digits.
27 no. with 3 digits.
Total: 39
Here:
3
5
8
35
53
38
83
58
85
335
353
338
383
358
385
535
553
538
583
558
585
835
853
838
883
858
885
33
55
88
333
555
888
335
533
833
388
588
855
2006-08-28 00:55:45 · answer #3 · answered by greenido 3 · 1⤊ 0⤋
You can choose the 1'st digit in one of 3 ways, the 2'nd digit in one of 3 ways, and the 3'rd digit in one of 3 ways. That makes 3*3*3 = 27 possible numbers.
Doug
2006-08-28 00:51:03 · answer #4 · answered by doug_donaghue 7 · 1⤊ 0⤋
27 i think
2006-08-28 00:53:03 · answer #5 · answered by jennyw 1 · 0⤊ 1⤋
15 i think
2006-08-28 00:48:28 · answer #6 · answered by Michelle 4 · 0⤊ 3⤋
9
It's like 3 nPr 3
2006-08-28 00:50:53 · answer #7 · answered by Maziar S 3 · 0⤊ 3⤋
3
5
8
33
35
38
53
55
58
83
85
88
333
335
338
353
355
358
383
385
388
533
535
538
553
555
558
583
585
588
833
835
838
853
855
858
883
885
888
39 Total
2006-08-28 00:51:56 · answer #8 · answered by Anonymous · 0⤊ 2⤋
nine maybe
2006-08-28 00:50:06 · answer #9 · answered by Eli_86 2 · 0⤊ 3⤋