If the population of a city was102,002 in the 2000 census and increases by a factor of 1.001 each year, what would be the population in the 2009
2006-08-27 16:07:33 · 5 answers · asked by dido45dido 3 in Education & Reference ➔ Homework Help
102,002 x 1.001 = 102,104.002
102,104.002 x 1.001 = 102,206.106
102,206.106 x 1.001 = 102,308.3121
102,308.3121 x 1.001 = 102,410.6204
102,410.6204 x 1.001 = 102,513.031
102,513.031 x 1.001 = 102,615,5441
102,615,5441 x 1.001 = 102,718.1594
102,718.1594 x 1.001 = 102,820.8778
102,820.8778 x 1.001 = 102,923.6987
population in 2009 is 102,923
2006-08-27 16:22:31 · answer #1 · answered by Anonymous · 0⤊ 0⤋
102002 is population in 2000
* 1.001
= population in 2001
continue multiplying each years product by 1.001 until you arrive at the 2009 population.
2006-08-27 23:15:09 · answer #2 · answered by Anonymous · 0⤊ 0⤋
9 x 1.001= a
102,002 + a= population in 2009
You have to do the figuring.
2006-08-27 23:13:44 · answer #3 · answered by *Larry P. he's for me* 4 · 0⤊ 0⤋
Take 102,002 and multiply it by 1.001 9 times. That will be your answer.
2006-08-27 23:13:08 · answer #4 · answered by Jim S 2 · 0⤊ 0⤋
102,002(1.001)^9 = your answer
^ = raised to the power of
2006-08-27 23:13:04 · answer #5 · answered by Ahmed 2 · 0⤊ 0⤋