one year 1,480 dogs in, 636 adopted out,the next year 1,459 dogs, and 1,119 are adopted out, what percentage increase is this in adoptions?
2006-08-27 12:17:48 · 3 answers · asked by VANESSA M 2 in Science & Mathematics ➔ Mathematics
636/1480 = 42.972972973%
1119/1459 = 76.6963673749%
76.6963673749 - 42.972972973 = 33.7233944019
33.7233944019/42.972972973
= 78.4758234511% increase
2006-08-27 12:27:37 · answer #1 · answered by MsMath 7 · 0⤊ 0⤋
Year 1: 636/1480 = 0.4297 or 42.97% adopted
Year 2: 1119/1459 = 0.7669 or 76.69% adopted
So, if we take:
100/42.97 = X/76.69 and solve for X
100*76.69 = X*42.97
7669 = X*42.97
X = 178.47
There was an increase of 178.47% adoption rate between the first and second year.
2006-08-27 13:03:27 · answer #2 · answered by cell-hell 3 · 0⤊ 0⤋
Increased Percentage
First year
636÷ 1480 = 0.42972973
Second year
1119 ÷ 1459 = 0.766963674
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - --
solving for the increase
0.42972973 ÷ 0.766963674 = 0.560299978
0.560299978 x 100 = 56.02999783 %
56.03 % Rounded to two decimal places
The answer is 56.03 %
2006-08-27 13:48:28 · answer #3 · answered by SAMUEL D 7 · 0⤊ 1⤋