They usually fit around my wiast,but end up being to short.I would like to find some jeans that look good but also affordable..Does Old Navy have any?
2006-08-27 11:07:17 · 11 answers · asked by Anonymous in Beauty & Style ➔ Fashion & Accessories
well i actually work there and yes we do! =] we have jeans that range in sizes 0 to 18 and they come in short, regular adn tall... for example/..... some jeans would be 10 long.....
2006-08-27 11:16:51 · answer #1 · answered by barbiedoll0309 1 · 0⤊ 0⤋
I think you should probably go to Macy's. Sure it sounds like so deparment store-y but its affordable jeans. And they have things that fit any type of woman.
2006-08-27 18:56:28 · answer #2 · answered by Fashionvista 3 · 0⤊ 0⤋
The Gap
2006-08-27 18:16:04 · answer #3 · answered by Anonymous · 0⤊ 0⤋
You can try Old Navy, I believe they have "tall" sizes.
Lane Bryant has talls, but they are usually for people over size 12. (My mom shops there)
or you can try www.jjill.com
2006-08-27 18:15:50 · answer #4 · answered by Jessie P 6 · 0⤊ 0⤋
Express makes jeans that are super-long and they always have great $20 sales on their jeans.
http://www.express.com
2006-08-27 18:13:25 · answer #5 · answered by Anonymous · 0⤊ 0⤋
I am the same height and I usually go to NY and Company or Gap.com....also NY and Company has great dress pants.
2006-08-27 18:15:22 · answer #6 · answered by BritLdy 5 · 0⤊ 0⤋
well i am 5'11 so i know how u feel...
express has long sizes and so does American Eagle...
its diffcult finding long enpugh jeans for me also!
Oh and Charlotte Russe has long jeans in some of their styles!
goodluck!
2006-08-27 18:22:55 · answer #7 · answered by Cassie 3 · 0⤊ 0⤋
You lucky girl! I can rarely find pants that don't need shortening. (That is, if I want them to fit the waist!)
2006-08-27 18:21:30 · answer #8 · answered by Two Lips 4 · 0⤊ 0⤋
try levis they have jeans for tall people
2006-08-27 18:23:53 · answer #9 · answered by Anonymous · 0⤊ 0⤋
Mabey but i know guess does
2006-08-27 18:10:12 · answer #10 · answered by couture*chick 2 · 0⤊ 0⤋