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Find the distance between the coordinates (2, 3) and (-5, 3)

2006-08-27 08:09:22 · 6 answers · asked by groundbrandon 3 in Education & Reference Homework Help

6 answers

Use the Pythagorean Theorem for this one: a^2 + b^2 = c^2.

When you use coordinates (x,y) and (X,Y), you just plug in the differences to find the lengths a and b, and then solve for c to determine the distance (or hypotaneuse):

(|x-X|)^2 + (|y-Y|)^2 = c^2

c= square root of [(|x-X|)^2 + (|y-Y|)^2]

This question is particularly easy, because both y-axis coordinates are on the value of 3, so a^2 = c^2. Therefore, by taking the square root of both, a = c, or:

|x-X| = c

You do the math!

2006-08-27 08:21:28 · answer #1 · answered by kookoonuts 2 · 0 0

well, the y coordinates are the same so you know that its a vertical line, now find the the distance between 2 and -7 by 2- (-7)

2006-08-27 08:28:17 · answer #2 · answered by ~*Prodigious*~ 3 · 0 0

The distance formula says that the distance d between any two points with coordinates (x1, y1) and (x2, y2) is given by the following equation: d = SQRT[(x2 - x1)2 + (y2 - y1)2].

Example

1. Problem: Find the distance between
(-2, 3) and (8, -1).

Solution: Plug any given information
into the distance equation.

d = SQRT[(8 - (-2))2 + (-1 - 3)2]

Simplify.

d = SQRT[102 + (-4)2]
d = SQRT(100 + 16)
d = 2(SQRT(29))

2006-08-27 08:14:25 · answer #3 · answered by Joe D 6 · 0 0

3-3 over 2-(-5)= 0/7...vertical line...i have no clue

2006-08-27 08:12:42 · answer #4 · answered by trufolife04 2 · 0 0

Try a squared + b squared = c squared.

I did not know how to type it using correct notation.

2006-08-27 08:13:59 · answer #5 · answered by perplexed 3 · 0 0

in degrees or what?

2006-08-27 08:11:44 · answer #6 · answered by Blue 4 · 0 0

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