Thank-you.
2006-08-27 07:04:53 · 11 answers · asked by Courtney 1 in Science & Mathematics ➔ Mathematics
Take out the 9: 9(c+5)
2006-08-27 07:08:05 · answer #1 · answered by Linda O'Chuffy 2 · 0⤊ 0⤋
You want to find what every term in the problem has in common, then factor it out. The best way to do this is by prime factorization. You can represent 9c as 3 * 3 * c. You can represent 45 as 5 * 3 * 3. Both of the terms have a 3 * 3 which is essentially 9. So you would factor out a 9 from both terms, and then you would right what is left over to finish it. SO...
9(c + 5)
2006-08-27 15:08:23 · answer #2 · answered by pecosbill2000 3 · 0⤊ 0⤋
Which is the common factor between 9c and 45??It is 9!
Therefore:
9(c+5) is your answer
2006-08-27 15:36:33 · answer #3 · answered by sbdy 1 · 0⤊ 0⤋
9c+45 -----take out the common factor '9'
=9(c+5)
2006-08-27 15:04:33 · answer #4 · answered by XXY~~ 1 · 0⤊ 0⤋
you can multiplt 9 by 1 and 9 by 45 getting 9(1c+5)or you can eliminate the 1 and just write 9(c+5)
2006-08-27 14:30:36 · answer #5 · answered by damelody 2 · 0⤊ 0⤋
9(c+5)
2006-08-27 14:07:16 · answer #6 · answered by natalie b 3 · 1⤊ 0⤋
take out a 9 which gives you 9(5+c)
2006-08-28 00:52:05 · answer #7 · answered by wormhole 2 · 0⤊ 0⤋
Take out the common factor. What is it?
2006-08-27 14:16:18 · answer #8 · answered by steiner1745 7 · 1⤊ 0⤋
Uhm E=mc2(squared) hehe
2006-08-27 14:06:58 · answer #9 · answered by Queen of Kings 4 · 0⤊ 2⤋
3x3xc+3x3x5
2006-08-27 14:07:27 · answer #10 · answered by Bonnie R 2 · 0⤊ 0⤋