C3H8 + 5 O2 ----> 3 CO2 + 4 H2O
I balanced the equation my self. Now, i need help with this part:
How many grams of carbon dioxide can be produced by burning 3.65 moles of propane? Assume that oxygen is the excess reagent in this reaction.
Please help me. I don't understand where to start and what do do?
2006-08-27 04:52:22 · 4 answers · asked by dingdong 1 in Science & Mathematics ➔ Chemistry
I'd help, but you'd think my answer was wrong.
Thanks for the 2 points!!
2006-08-27 22:44:23 · answer #1 · answered by Mr. G 6 · 0⤊ 0⤋
1 mole of propane makes 3 moles of CO2 (3 x 44 grms)
3.65 would make 3.65 x 3 x 44 grms
= 486.2 grms
2006-08-27 14:16:35 · answer #2 · answered by lykovetos 5 · 0⤊ 0⤋
1 mole of propane ---> 3 moles of CO2
3.65 moles of propane ---> 3*3.65 moles of CO2
1 mole of CO2 = 44g CO2
3*3.65 moles of CO2 = 3*3.65*44 = 481.8g of CO2
2006-08-27 13:10:58 · answer #3 · answered by andreicnx 3 · 0⤊ 0⤋
one mole of propane(44g) shall produce 3mol of carbon dioxide(3x44g) Hence 3.65 mol of propane will produce 3.65x44g=160.6g carbondioxide
2006-08-27 12:02:40 · answer #4 · answered by sachidananda murthy ts 1 · 0⤊ 1⤋